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Sergeeva-Olga [200]
1 year ago
7

How can I find X and Y in this diagram?

Mathematics
1 answer:
Nastasia [14]1 year ago
7 0

Given the figure of a cyclic quadrilateral

The sum of the opposite angles = 180

so, we can write the following equations:

\begin{gathered} x+100=180\rightarrow(1) \\ 2y+102=180\rightarrow(2) \end{gathered}

we will find (x) from equation (1):

x = 180 - 100 = 80

We will find (y) from equation (2):

2y = 180 - 102

2y = 78

y=78/2 = 39

So, the answer will be:

x = 80

y = 39

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Suppose 300 nursing students took a certification test that is worth 100 points.
Alja [10]

Answer:

225 students scored 65 or better and 75 students scored 88 or better.

Step-by-step explanation:

We are given that The five-number summary for the scores of 300 nursing students are given :

Minimum = 40

Q_1 = 65

Median = 82

Q_3 = 88

Maximum = 100

Q_1 is the first quartile and is the median of the lower half of the data set. 25% of the numbers in the data set lie below Q_1 and about 75% lie above Q_1 .

Q_3 is the third quartile and is the median of the upper half of the data set. 75% of the numbers in the data set lie belowQ_3 and about 25% lie above Q_3

i) .About how many students scored 65 or better?

Q_1 = 65

Since we know that 75% lie above Q_1 .

So, Number of students  scored 65 or better = 75\% \times 300 = \frac{75}{100} \times 300 =225

ii)About how many students scored 88 or better?

Q_3 = 88

Since we know that 25% lie above Q_3

So, Number of students scored 88 or better = 25\% \times 300 = \frac{25}{100} \times 300 =75

Hence 225 students scored 65 or better and 75 students scored 88 or better.

7 0
3 years ago
Convert 3.5 • 10^4 to standard form.
timofeeve [1]

3.5\cdot10^4=35000

7 0
3 years ago
Which choice is equivalent to the product below when x > 0?
anastassius [24]

The product below is equivalent when x > 0 is <u>1/9</u>

       

<h3>Resolution - Explanation</h3>

Square root is a real number x multiplied by itself - which results in a perfect value, where it is possible to calculate the real proof (which is the square root).

             

Given the expression, \large \sf \sqrt{\dfrac{1}{x^{2} } }  \cdot \sqrt{\dfrac{x^{2} }{81} }, first step: we will calculate the root of the numerator and denominator of this fraction:

<u />

<u />\\\large \sf \sqrt{\dfrac{1}{x^{2} } }  \cdot \sqrt{\dfrac{x^{2} }{81} }

\large \sf \dfrac{\sqrt{1} }{\sqrt{x^{2} } }  \rightarrow \dfrac{1}{x}

\large \sf \dfrac{\sqrt{x^{2} } }{\sqrt{81 } }  \rightarrow \dfrac{x}{9}\\\\

Step two: rearranging the expression and canceling the common factors x, we will have,:

\\\large \sf \dfrac{1}{\not x} \cdot \dfrac{\not x}{9}

\pink{\boxed{\large \sf \dfrac{1}{9} }}\\

Therefore, the final answer to this multiplication will be 1/9.

6 0
2 years ago
What is the result of 2÷4/10​
leonid [27]

Answer:

0.05

Step-by-step explanation:

that is the answer

6 0
3 years ago
Read 2 more answers
What 2 numbers multiply to be 108 but subtract to be 6
mel-nik [20]
No 2 numbers do this.

Possible numbers that can multiply to 108:

<span>1 x 108 = 108
2 x 54 = 108
3 x 36 = 108
4 x 27 = 108
6 x 18 = 108
9 x 12 = 108
12 x 9 = 108
18 x 6 = 108
27 x 4 = 108
36 x 3 = 108
54 x 2 = 108
108 x 1 = 108 

Possible numbers on that list that when subtracted equate to 6:

None</span>
3 0
3 years ago
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