This isn't really a geometry problem. It's just an addition of fractions.
You know that 'perimeter' means 'the distance all the way around'.
And you know the length of all the sides of the parallelogram.
All you need to do is add them up !
(13/12) + (3/13) + (13/12) + (3/13) = the perimeter
Notice that two of the sides are equal, and the other two sides are also equal.
So you can make the job a little easier if you add up the twelfths first
(13/12) + (13/12) = 26/12
and then add up the thirteenths ...
(3/13) + (3/13) = 6/13 .
Now, the perimeter looks a little bit less complicated.
It's just
(26/12) + (6/13) = the perimeter.
This is the tough part. Before you can add fractions, they need to have
a common denominator.
The smallest common denominator for 12ths and 13ths is <em>156 </em>!
Change each fraction to (<em>something over 156</em>), and add um up.
I'll leave that part to you.
Bro I’m rly sorry but I don’t know the answer to this
To factor this quadratic function, there are many ways that you can do this, the most common approach used to graph anything would be to make a table of values. Basically, make a chart with x coordinates on one side and y coordinates on the other side. Pick any values for your x coordinates and then find the correct y coordinate that results when you place that specific x coordinate into the function. After getting many points, plot those points on the grid and it should give you a parabola.
Another way to graph the function is to find the x intercepts, you can do this by setting the function to zero, and factoring the trinomial, using the appropriate method, then find the x intercepts
y = 2x^2 - 8x + 6
0 = (2x^2 - 6x - 2x + 6)
0 = 2x(x - 3) - 2(x - 3)
0 = (2x - 2)(x - 3).
Answer:
(2, 3)
Step-by-step explanation:
lines with undefined slopes are vertical lines