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melisa1 [442]
1 year ago
15

help pleaseeee, i managed to get the right answer but the way i did it doesnt feel right, can somebody please answer so i can se

e what to do​

Mathematics
1 answer:
irga5000 [103]1 year ago
4 0

Answer:

≈ 4,22 m

Step-by-step explanation:

volume = 20000L = 20000 dm^3 = 20 m^3

diameter = 2,4m

the volume of a cilinder is π * r^2 * h (height)

20 = π * 1,2^2 * h

h = \frac{20}{\pi * 1,44} \\ ≈ 4,42 m

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Can I get help solving this graph please?
Daniel [21]
see the attached figure with the letters

1) find m(x) in the interval A,B
A (0,100)  B(50,40) -------------- > p=(y2-y1(/(x2-x1)=(40-100)/(50-0)=-6/5
m=px+b---------- > 100=(-6/5)*0 +b------------- > b=100
mAB=(-6/5)x+100

2) find m(x) in the interval B,C
B(50,40)  C(100,100) -------------- > p=(y2-y1(/(x2-x1)=(100-40)/(100-50)=6/5
m=px+b---------- > 40=(6/5)*50 +b------------- > b=-20
mBC=(6/5)x-20

3) find n(x) in the interval A,B
A (0,0)  B(50,60) -------------- > p=(y2-y1(/(x2-x1)=(60)/(50)=6/5
n=px+b---------- > 0=(6/5)*0 +b------------- > b=0
nAB=(6/5)x

4) find n(x) in the interval B,C
B(50,60)  C(100,90) -------------- > p=(y2-y1(/(x2-x1)=(90-60)/(100-50)=3/5
n=px+b---------- > 60=(3/5)*50 +b------------- > b=30
nBC=(3/5)x+30

5) find h(x) = n(m(x)) in the interval A,B
mAB=(-6/5)x+100
nAB=(6/5)x
then 
n(m(x))=(6/5)*[(-6/5)x+100]=(-36/25)x+120
h(x)=(-36/25)x+120
find <span>h'(x) 
</span>h'(x)=-36/25=-1.44

6) find h(x) = n(m(x)) in the interval B,C
mBC=(6/5)x-20
nBC=(3/5)x+30
then 
n(m(x))=(3/5)*[(6/5)x-20]+30 =(18/25)x-12+30=(18/25)x+18
h(x)=(18/25)x+18
find h'(x) 
h'(x)=18/25=0.72 

for the interval (A,B) h'(x)=-1.44
for the interval (B,C) h'(x)= 0.72

<span> h'(x) = 1.44 ------------ > not exist</span>

8 0
2 years ago
Can someone check this for me thanks so much
Zinaida [17]

Answer:

that looks like it is right

3 0
2 years ago
Read 2 more answers
Gina bought 2.5 pounds of peaches that cost $1.38 per pound at the grocery store. Amy went to the local farmer’s market and purc
patriot [66]
Gina spent $3.45 in total. amy spent $3.43 in total. so gina spent more money and she spent 2 cents more
4 0
2 years ago
Read 2 more answers
ms shaddal writes 3g = 51 and 15 16 17 on the board tell if each value in the set is a solution of the equation show your work b
Rudiy27

Answer:

17 is the solution to the equation

Step-by-step explanation:

3g=51

/3   /3

g=17

7 0
3 years ago
What is the solution to (x^3/4 over y^-1/2)^6
Mariulka [41]
Y = 1/3 x - 10
2x + y = 4
2x + 1/3 x - 10 = 4
7/3 x = 14
x = 6
y = 1/3(6) - 10 = 2 - 10 = -8
Therefore solution is (6, -8)

hope that helps ;)
7 0
3 years ago
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