H=2ft
d=6 ft
r=d/2
r=6/2=3ft
V= π•r^2•h
V=3.14•3^2•2
V=3.14•9•2
V=56.52 ft3
V~56.5ft3
<h3>Answer 1a :- </h3>
Here we can solve this question using<em> </em><em>Unitary</em><em> </em><em>Method</em><em> </em><em>.</em> As ;
→ In 17hrs the boat travels 452km
→ In 1hr the boat will travel 452km/17
→ In 9hrs the boat will travel 452/17km * 9 = 239.29km

<h3>Answer 1b:-</h3>
→ A car can travel 156km on 13L gasoline .
→ It will travel 1km on 13/156L of gasoline .
→ It will travel 480km on 13/156*480L = 40L of gasoline .

<h3>
Answer 2a :-</h3>
→ A boat can go 180 miles on 60L gasoline.
→ It will go 1mile in 60/180L of gasoline.
→ It will go 306 miles in 60/180*306L = 102L of gasoline .

<h3>Answer 2b :-</h3>
→ On 51L of gasoline a car can go 408km
→ On 1L of gasoline car will go 408/51 km
→ On 11L of gasoline it will go 408/51*11L = 88km

5x5 - 10x = 0
5x5 - 10x = 5x • (x4 - 2)
Answer:
its 5/4! haha i used to be good at this when i was in 6th grade:)
Answer:
Mr. Chang will have 15714.90 dollars.
Step-by-step explanation:
p = 650
r = 
Number of periods or n = 
Future value formula is : ![p[\frac{(1+r)^{n}-1}{r} ]](https://tex.z-dn.net/?f=p%5B%5Cfrac%7B%281%2Br%29%5E%7Bn%7D-1%7D%7Br%7D%20%5D)
Putting the values in formula we get;
![650[\frac{(1+0.0195)^{20}-1}{0.0195} ]](https://tex.z-dn.net/?f=650%5B%5Cfrac%7B%281%2B0.0195%29%5E%7B20%7D-1%7D%7B0.0195%7D%20%5D)
= $15714.90
Hence, Mr. Chang will have 15714.90 dollars.