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4 years ago

Write an equation and solve. Round to the nearest hundredth where necessary.

Mathematics

2 answers:

saw5 [17]4 years ago

7 0

The third option represents the proper calculation for 80% of 88

Murrr4er [49]4 years ago

5 0

$\sf Hello!$

$\sf Let\: the \:required\: number\:be\: x$

$\sf Then,$

$\sf x = \sf 80$ % of $\sf 88$

⇒ $\sf x = \dfrac{\sf 80}{\sf 100} × \sf 88$

⇒ $\sf x = \dfrac{\sf 4}{\sf 5} × 88$

⇒ $\boxed{\sf x = 70.4}$

$\sf Therefore,$
$\sf 80$ % $\sf of \:88\: is\: C.\: n = 0.8 \cdot 88; \:70.4$

~ $\sf iCarl$

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which of the following expresses the possible number of positive real solutions for the polynomial equation shown below

Nookie1986 [14]

The polynomial equation x³ - 4x² - 7x + 28 = 0, has solutions -√7, √7, and 4, among which √7 and 4 are positive real solutions. Hence we have two positive real solutions. Hence, option D is the right choice.

In the question, we are asked for the number of positive real solutions for the polynomial equation, x³ - 4x² - 7x + 28 = 0.

To find the solutions, we do as follows:

x³ - 4x² - 7x + 28 = 0,

or, (x³ - 7x) - (4x² + 28) = 0 {Grouping},

or, x(x² - 7) - 4(x² - 7) = 0 {Taking common},

or, (x - 4)(x² - 7) = 0 {Grouping},

or, (x - 4)(x + √7)(x - √7) = 0 {Using the formula: $a^2 - b^2 = (a+b)(a-b)$ }.

By the zero-product rule, the solutions are:

x - 4 = 0, or, x = 4,

x + √7 = 0, or, x = -√7,

x - √7 = 0, or, x = √7.

Thus, the positive real solutions are 4, and √7. Hence, there are two positive real solutions.

Thus, the polynomial equation x³ - 4x² - 7x + 28 = 0, has solutions -√7, √7, and 4, among which √7 and 4 are positive real solutions. Hence we have two positive real solutions. Hence, option D is the right choice.

Learn more about polynomials at

brainly.com/question/1550365

#SPJ4

The complete question is:

"Which of the following expresses the possible number of positive real solutions for the polynomial equation shown below?

x³-4x²-7x+28=0

a. two or zero

b. three or one

c. one

d. two"

5 0

2 years ago