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Mashcka [7]
3 years ago
12

How many unit squares are shaded in a 12 by 12 border grid

Mathematics
2 answers:
Oduvanchick [21]3 years ago
8 0
So you just have to multiply 12 times 12 which is 144
torisob [31]3 years ago
3 0
12 ×12 =144 squares. an array is found by multiplying length units by width units. Much like finding the area
You might be interested in
I need help with 3, 4, 5, and 6
Ostrovityanka [42]
3. The answer is 18 because 12➗4= 3 so 6*3=18
3 0
3 years ago
Amanda has $75 in her savings accountwhile Julie has $30 in her savings account Amanda adds $5 per week into her allowance and J
ELEN [110]

Answer:

$100

Step-by-step explanation:

Every week Amanda adds $5 and every week Julia adds $14. So all you have ti do is add $5 to Amanda's account and $14 to Julia's account until you have the same amount of money for the both of them.

5 0
3 years ago
If a positive integer is equal to the following product: 25b3c425b3c4, where b and c are distinct prime numbers greater than 2,
Vlad [161]

Answer: 64 distinct even factors

Step-by-step explanation:

let the 2 distinct numbers be b and c and the integer is expected to be 25b3c425b3c4

since b, c > 2 and prime numbers,

potential options include 3, 5, and 7

hence the likelihoods are (b = 3, c = 5), (b = 5, c = 3), (b = 3, c = 7), (b = 7, c = 3), (b = 5, c = 7), (b = 7, c = 5)

Possibility 1 (b = 3, c = 5)

integer is now 253354253354

the distinct even factors = 2, 202, 262, 1934, 19802, 26462, 195334, 253354, 2000002, 2594062, 19148534, 25588754, 262000262, 1934001934, 2508457954, 253354253354

number of distinct even factors = 16

Possibility 2 (b = 5, c = 3)

integer is now 255334255334

the distinct even factors = 2, 86, 202, 5938, 8686, 19802, 253354, 599738, 851486, 2000002, 25788734, 58792138, 25588754, 86000086, 2528061934, 1934001934, 5938005938, 253354253354

number of distinct even factors = 18

Possibility 3 (b = 3, c = 7)

integer is now 253374253374

the distinct even factors = 2, 6, 22, 66, 202, 242, 606, 698, 726, 2094, 2222, 6666, 7678, 19802, 23034, 24442, 59406, 70498, 73326, 84458, 211494, 217822, 253374, 653466, 775478, 2000002, 2326434, 2396042, 6000006, 6910898, 7188126, 8530258, 20732694, 22000022, 25590774, 66000066, 76019878, 228059634, 242000242, 698000698, 726000726, 836218658, 2094002094, 2508655974, 7678007678, 23034023034, 84458084458,253354253354

number of distinct even factors = 48

Possibility 4 (b = 7, c = 3)

integer is now 257334257334

the distinct even factors = 2, 6, 14, 22, 42, 66, 154, 202, 462, 606, 1114, 1414, 2222, 3342, 4242, 6666, 7798, 12254, 15554, 19802, 23394, 36762, 46662, 59406, 85778, 112514, 138614, 217822, 257334, 337542, 415842, 653466, 787598, 1237654, 1524754, 2000002, 2362794, 3712962, 4574262, 6000006, 8663578, 11029714, 14000014, 22000022, 25990734, 33089142, 42000042, 66000066, 77207998, 121326854, 154000154, 231623994, 363980562, 462000462, 849287978, 1114001114, 2547863934, 3342003342, 7798007798, 12254012254, 23394023394, 36762036762, 85778085778, 257334257334

number of distinct even factors = 64

Possibility 5 (b = 5, c = 7)

integer is now 255374255374

the distinct even factors = 2, 14, 34, 58, 74, 202, 238, 406, 518, 986, 1258, 1414, 2146, 3434, 5858, 6902, 7474, 8806, 15022, 19802, 24038, 36482, 41006, 52318, 99586, 127058, 138614, 216746, 255374, 336634, 574258, 697102, 732674, 889406, 1517222, 2000002, 2356438, 3684682, 4019806, 5128718, 9762386, 12455458, 14000014, 21247546, 25792774, 34000034, 58000058, 68336702, 74000074, 87188206, 148732822, 238000238, 361208282, 406000406, 518000518, 986000986, 1258001258, 2146002146, 2528457974, 6902006902, 8806008806, 15022015022, 36482036482, 255374255374

number of distinct even factors = 64

Possibility 6 (b = 7, c = 5)

integer is now 257354257354

the distinct even factors = 2, 202, 19802, 257354, 2000002, 25992754, 2548061954, 257354257354

number of distinct even factors = 8

From the six possibilities, the highest number of likely distinct even factors is 64

7 0
3 years ago
Pls help me, I really dont understand
Stella [2.4K]

Answer:

-2.5x-.5

y=\frac{2}{3}x-1

draw the dotted line (3/7)x-3 and shade below it

Step-by-step explanation:

First, we need the slope

Use the slope formula:

\frac{Y_2-Y_1}{X_2-x_1}=\frac{2-(-8)}{-1-3}=\frac{10}{-4}=-2.5

so we have

y= -2.5x+b

Solve for b by plugging in coordiantes

-8= -2.5(3)+b

-8= -7.5+b

b= -.5

Put it together and get -2.5x-.5

2.)

A line is parallel to another line if they have the same slope (and different y intercepts)

So in the formula y=mx+b we knowe that m= 2/3

Now it's just a matter of solving for B

plug in the required coordinate to do this

-1=(2/3)*0+b

-1= b

Put it all together to get

y=\frac{2}{3}x-1

3.)

put this into slope intercept form

3x-7y>21

3x-21 > 7y

(3/7)x-3 >y

To graph this just draw a dotted line with the equation (3/7)x-3 and shade everything below it (use de_smos if you're stuck)

7 0
3 years ago
Trey is putting up a fence around a 750 foot by 540 foot lot. How many feet of fence dose he need?
anygoal [31]

Given:

The length of the lot l= 750ft

The width of the plot w= 540 ft

Required:

Find the required fence.

Explanation:

The perimeter of the rectangle is given by the formula.

P=2(length+width)

Thus the required fence for the lot

\begin{gathered} =2(750+540) \\ =2(1290) \\ =2580\text{ ft} \end{gathered}

Final answer:

The required fence is 2580 ft.

6 0
1 year ago
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