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9 months ago

15. Which rule was used to create the arithmetic sequence below?

Mathematics

1 answer:

Nikolay [14]9 months ago

4 0

The rule used to create the arithmetic sequence -2, -4, -6, -8,.. is an = -2 - 2(n-1)

The arithmetic sequence is

-2, -4, -6, -8,...

The initial term = -2

The common difference = The second term - The first term

= -4 - (-2)

= -4 + 2

= -2

The nth term of the arithmetic sequence is

an = a+ (n-1) d

Where a is the initial term

an is the nth term

d is the common difference

Substitute the values in the equation

an = -2 + (n-1)(-2)

Rearrange the terms

an = -2 -2(n-1)

Hence, the rule used to create the arithmetic sequence -2, -4, -6, -8,.. is an = -2 - 2(n-1)

Learn more about arithmetic sequence here

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2 years ago

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3 years ago

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Answer:

The solution is $\displaystyle x=1\pm \sqrt{47}$ . Fourth option

Explanation:

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Move all the terms from the right to the left side of the equation, a zero in the right side:

$2x^2+3x-7-x^2-5x-39=0$

Join all like terms:

$x^2-2x-46=0$

The general form of the quadratic equation is:

$ax^2+bx+c=0$

Solve the quadratic equation by using the formula:

$\displaystyle x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

In our equation: a=1, b=-2, c=-46

Substituting into the formula:

$\displaystyle x=\frac{-(-2)\pm \sqrt{(-2)^2-4(1)(-46)}}{2(1)}$

$\displaystyle x=\frac{2\pm \sqrt{4+184}}{2}$

$\displaystyle x=\frac{2\pm \sqrt{188}}{2}$

Since 188=4*47

$\displaystyle x=\frac{2\pm \sqrt{4*47}}{2}$

Take the square root of 4:

$\displaystyle x=\frac{2\pm 2\sqrt{47}}{2}$

Divide by 2:

$\displaystyle x=1\pm \sqrt{47}$

First option: Incorrect. The answer does not match

Second option: Incorrect. The answer does not match

Third option: Incorrect. The answer does not match

Fourth option: Correct. The answer matches exactly this option

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