We need to find what percentage represents the number of Hershey's Cookie Crème Candy Bars in each package, and then compare which one is better.
For package A.
It has 13 Hershey's Cookie Crème Candy Bars out of 25. To find which percentage is 13 out of 25 we do the following:
• Divide 100 by the total amount of candy 25, and multiply the result by 13:

we get the following percentage:

Package A has 52% of Hershey's Cookie Crème Candy Bars.
For package B.
It has 11 Hershey's Cookie Crème Candy Bars out of 20. we do the same as before to find the percentage, only that this time, instead of dividing by 25, we divide 100 by 20, and intead of multiplying by 12, we multiply by 11:

The result is:

Package B has 55% of Hershey's Cookie Crème Candy Bars.
Which package should Alladin buy? He should buy Package B because it has a greater percentage.
For any distribution, the sum of the probabilities of all possible outcomes must be 1. In this case, we have to have

We're told that
, and we're given other probabilities, so we have

The expected number of calls would be
![E[X]=\displaystyle\sum_xx\,P(X=x)](https://tex.z-dn.net/?f=E%5BX%5D%3D%5Cdisplaystyle%5Csum_xx%5C%2CP%28X%3Dx%29)
![E[X]=0\,P(X=0)+1\,P(X=1)+\cdots+4\,P(X=4)](https://tex.z-dn.net/?f=E%5BX%5D%3D0%5C%2CP%28X%3D0%29%2B1%5C%2CP%28X%3D1%29%2B%5Ccdots%2B4%5C%2CP%28X%3D4%29)
![E[X]=1.4](https://tex.z-dn.net/?f=E%5BX%5D%3D1.4)
Given:
The equation is:

To find:
The solution for the given equation to the nearest hundredth.
Solution:
We have,

Divide both sides by 3.


Taking ln on both sides, we get

![[\because \ln e^x=x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Cln%20e%5Ex%3Dx%5D)
Divide both sides by 2.4.

![[\because \ln (90)\approx 4.4998]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Cln%20%2890%29%5Capprox%204.4998%5D)

Round the value to the nearest hundredth (two decimal place)

Therefore, the value of K is 1.87.