All categories

1 year ago

What is the lcm of 6 and 8

Mathematics

1 answer:

Dafna1 [17]1 year ago

5 0

Answer:

Explanation:

Method 1

First, list the multiples of both numbers:

$undefined$

To find the lowest common multiple (LCM) of 6 and 8, first express the numbers as a product of its prime factors.

$\begin{gathered} 6=2\times3 \\ 8=2\times2\times2=2^3 \end{gathered}$

Next, pick the highest powers for each of the numbers:

$\begin{gathered} \text{LCM}=2^3\times3 \\ =8\times3 \\ =24 \end{gathered}$

You might be interested in

8 (p + 8 7 + 2q)<br><br> help me pleas!!!

77julia77 [94]

Answer:

8p +56 +16q

Step-by-step explanation:

8 (p+7+2q)

If we distribute the 8 into everything in the parenthesis, we get:

8p +56 +16q

5 0

3 years ago

HELP!!!

uranmaximum [27]

Step-by-step explanation:

10 gallons of gas is $29.50

10 gallons of gas = $29.50

10 gallons of gas / 10 = $29.50 / 10

1 gallon of gas = $2.95

Per x gallons of gas,

1 gallon of gas * x = $2.95 * x

x gallons of gas = $2.95 * x

7 0

3 years ago

BEST ANSWER GETS BRAINLYEST

denis23 [38]

0.024 is 2.4%
0.125 is 12.5%
0.05 is 5%

Showing the workMultiply 0.05 by 100 to convert to percent:

<span>0.05 × 100 = </span>5 %

0.5 is 50%
Showing the work - Multiply 0.5 by 100 to convert to percent:

0.5 × 100 = 50 %
Showing the work -multiply 0.024 by 100 to convert to percent:

0.024 × 100 = 2.4 %

6 0

3 years ago

Read 2 more answers

Determine the values of the constants b and c so that the function given below is differentiable. f(x)={2xbx2+cxx≤1x>1

Lera25 [3.4K]

Assuming the function is

$f(x)=\begin{cases}2x&\text{for }x\le1\\bx^2+cx&\text{for }x>1\end{cases}$

For $f(x)$ to be differentiable, it necessarily has to be continuous. For this condition to be met, we need

$\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1^+}f(x)=f(1)$
$\iff\displaystyle\lim_{x\to1}2x=\lim_{x\to1}(bx^2+cx)$
$\iff2=b+c$

For the derivative to exist, the one-sided limits of the derivative must also exist and be equal. We have

$f'(x)=\begin{cases}2&\text{for }x1\end{cases}$

$\displaystyle\lim_{x\to1^-}2=\lim_{x\to1^+}(2bx+c)$
$\iff2=2b+c$

Now we solve for $b$ and $c$ :

$\begin{cases}b+c=2\\2b+c=2\end{cases}\implies b=0,c=2$

5 0

3 years ago

14 bugs are crawling on the steps. Some of the bugs are black, and 4 are

docker41 [41]

Answer:

b = 14-4

Step-by-step explanation:

Let the number of black bugs be b

Let the number of green bugs be g

If 14 bugs are crawling on the step, then;

b + g = 14 ....1

If there are 4 green bugs, then g = 4

Substitute g = 4 into the equation

b + g = 14

b + 4 = 14

b = 14 - 4

Hence the sentence that can be required to find the number of black bugs is b = 14-4

8 0

3 years ago