Answer:
don't know
Step-by-step explanation:
Short answer 34/13Start by converting both to improper fractions.
8 1/2 = (2*8 + 1)/2 = 17/2
3 1/4 = (3*4 + 1)/4 = 13/4
Next set up a 4 layer fraction

Invert the lower fraction and multiply

Cancel the 2 and the 4 leaving you with a 2 in the numerator.
A=pi(radius^2)
630/3.14=200.64
radius=14.16 feet
C=2(pi)(radius)
=3.14(2)(14.16)
=6.28(14.16)
C=88.92
88.92<100
Yes! He has enough fencing to enclose the circular area.
Answer:
1250 m²
Step-by-step explanation:
Let x and y denote the sides of the rectangular research plot.
Thus, area is;
A = xy
Now, we are told that end of the plot already has an erected wall. This means we are left with 3 sides to work with.
Thus, if y is the erected wall, and we are using 100m wire for the remaining sides, it means;
2x + y = 100
Thus, y = 100 - 2x
Since A = xy
We have; A = x(100 - 2x)
A = 100x - 2x²
At maximum area, dA/dx = 0.thus;
dA/dx = 100 - 4x
-4x + 100 = 0
4x = 100
x = 100/4
x = 25
Let's confirm if it is maximum from d²A/dx²
d²A/dx² = -4. This is less than 0 and thus it's maximum.
Let's plug in 25 for x in the area equation;
A_max = 25(100 - 2(25))
A_max = 1250 m²
Answer:
x = 125
Step-by-step explanation:
x = 160 - 35
x = 125