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alex41 [277]
2 years ago
8

The question is above. I posted a pic. Pls help

Mathematics
1 answer:
AleksandrR [38]2 years ago
8 0

A petal in the third quadrant is generated when r is negative.

\begin{gathered} \text{ On the interval (}\frac{\pi}{6},\frac{\pi}{3})\text{ ,} \\ \cos (3\theta)\in\lbrack0,-1\rbrack \end{gathered}

Therefore,

r=6\cos (3\theta)\text{ is in \lbrack{}0,-6\rbrack on the interval (}\frac{\pi}{6},\frac{\pi}{3})

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Suppose you pick two cards from a deck of 52 playing cards. What is the probability that they are both queens?
photoshop1234 [79]

Answer:

0.45% probability that they are both queens.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes

The combinations formula is important in this problem:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

Desired outcomes

You want 2 queens. Four cards are queens. I am going to call then A,B,C,D. A and B is the same outcome as B and A. That is, the order is not important, so this is why we use the combinations formula.

The number of desired outcomes is a combinations of 2 cards from a set of 4(queens). So

D = C_{4,2} = \frac{4!}{2!(4-2)!} = 6

Total outcomes

Combinations of 2 from a set of 52(number of playing cards). So

T = C_{52,2} = \frac{52!}{2!(52-2)!} = 1326

What is the probability that they are both queens?

P = \frac{D}{T} = \frac{6}{1326} = 0.0045

0.45% probability that they are both queens.

4 0
3 years ago
a. the​ function's domain; b. the​ function's range; c. the​ x-intercepts, if​ any; d. the​ y-intercept, if​ any; and e. the mis
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c or e

Step-by-step explanation:

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What two products do you get when you cross-multiply the fractions 2/5 and 3/8?
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explanation:
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4 years ago
See attachment below. Please answer. Thank you.
KonstantinChe [14]

Hi

The probability of landing a green side up is 2 / 6 .

Hope this helps

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3 years ago
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(5x^3-5x-8)+(2x^3+4x+2)
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7 0
4 years ago
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