The question is above. I posted a pic. Pls help

Mathematics

1 answer:

AleksandrR [38]1 year ago

8 0

A petal in the third quadrant is generated when r is negative.

$\begin{gathered} \text{ On the interval (}\frac{\pi}{6},\frac{\pi}{3})\text{ ,} \\ \cos (3\theta)\in\lbrack0,-1\rbrack \end{gathered}$

Therefore,

$r=6\cos (3\theta)\text{ is in \lbrack{}0,-6\rbrack on the interval (}\frac{\pi}{6},\frac{\pi}{3})$

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Find angle B. What is angle B.

julsineya [31]

Answer:

B=45 Degrees

Step-by-step explanation:

You can use law of sines to answer. Law of Sines states that $\frac{sin(a)}{A} =\frac{sin(b)}{B}$ . That means that $\frac{sin(60)}{4\sqrt{6} }=\frac{sin(b)}{8}$ . Multiplying 8 to both sides gives us $\frac{8sin(60)}{4\sqrt{6} }=sin(b)$ . By using inverse of sin, we get $b = sin^{-1} (\frac{8sin(60)}{4\sqrt{6} } )$ . Plugging that into a calculator gives us b=45 degrees.