Which equation can be used to solve for b? Triangle A B C is shown. Angle A C B is 90 degrees and angle C B A is 30 degrees. The
length of side B C is 8 feet, the length of B A is c, and the length of C A is b. b = (8)tan(30o) b = StartFraction 8 Over tangent (30 degrees) EndFraction b = (8)sin(30o) b = StartFraction 8 Over sine (30 degrees) EndFraction
2 answers:
Answer:
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
In the right triangle ABC, the tangent of angle of 30 degrees is equal to divide the opposite side to the angle of 30 degrees (AC) by the adjacent side to the angle of 30 degrees (BC)
substitute the given values
Solve for b
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Answer:
15 miles per hour is the speed of the slower train.
Step-by-step explanation:
As given in the figure attached,
Let the speed of train 1 is v and train 2 is u.
Therefore, distance traveled in 2 hours by train 1 will be = 2v miles
and distance traveled by train 2 will be = 2u miles
Now we can see in the figure a right angle triangle is formed by the two trains.
AB² + BC² = AC²
(2v)² + (2u)²= (65.30)²
4v² + 4u² = 4264.09
Now we divide this equation by 4
v² + u² = 1066.02
If speed of the slower train is v miles per hour then as per statement of the question.
u = v - 14
v = u + 14
By putting the value of v in the equation
(u + 14)² + u² = 1066
u² + 196 + 28u + u² = 1066
2u² + 28u + 196 = 1066
2u² + 28u + 196 - 1066 = 0
2u² + 28u - 870 = 0
By diving this equation by 2
u² + 14u - 435 = 0
u² + 29u - 15u - 435 = 0
u(u + 29) - 15(u + 29) = 0
(u + 29)(u - 15) = 0
u = -29, 15
Since speed can not be with negative notation so u = 15 miles per hour will be the speed.
Therefore, 15 miles per hour is the speed of the slower train.
