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ValentinkaMS [17]
3 years ago
14

I need help very fast please!

Mathematics
2 answers:
postnew [5]3 years ago
7 0
I’m not sure maybe D
Nadusha1986 [10]3 years ago
3 0
I think it is B not sure tho:)
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Abigail's car uses 3 2/3 gallons of gas every hour on a long distance trip. How many gallons does the car use in 8 1/2 hours?
san4es73 [151]

Answer:

31.166 repeating

Step-by-step explanation:

3 0
3 years ago
Which equation could be used to find the length of the hypotenuse?
Julli [10]

Answer:

2^2 +5^2 = c^2

Step-by-step explanation:

We can use the Pythagorean theorem to solve for c

a^2 + b^2 =c^2  where a and b are the legs and c is the hypotenuse

2^2 +5^2 = c^2

4+25 = c^2

29 =c^2


3 0
3 years ago
Read 2 more answers
PLEASE HELP QUICKLY!!! A student's parents offer him one of two options to receive scholarship money for college.
emmainna [20.7K]

Answer:

A = $47,500.00, B = $65,536.00; B, because he receives $18,036.00 more

Step-by-step explanation:

Option A Versus Option B

Option A                                                Option B

Day Amount Deposited                        Day Amount Deposited

0     $40,000.00                                    0       $1.00

1      $40,250.00                                     1        $2.00

2      $40,500.00                                    2       $4.00

...

30   $47,500                                          16      $65,536.00

Answer:

A = $47,500.00, B = $65,536.00; B, because he receives $18,036.00 more

7 0
3 years ago
Please answer will mark brainliest need to find the slope!
stepan [7]

Answer:

0.3

Step-by-step explanation:

7 0
4 years ago
If f(x)f(x) is an exponential function where f(1.5)=5f(1.5)=5 and f(7.5)=79f(7.5)=79, then find the value of f(3)f(3), to the ne
stiv31 [10]

Answer: 7.93

Step-by-step explanation:

Given

f(x) is an exponential function. Suppose f(x) is ae^{bx}

f(1.5)=5\ \text{and}\ f(7.5)=79

\Rightarrow 5=ae^{1.5b}\\\Rightarrow \ln 5=\ln a-1.5b\quad \ldots(i)

Similarly,

\Rightarrow 79=ae^{7.5b}\\\Rightarrow \ln(79)=\ln a+7.5b\quad \ldots(ii)

Subtract (i) and (ii)

\Rightarrow \ln (79)-\ln (5)=9b\\\Rightarrow \ln (\frac{79}{5})=9b\\\\\Rightarrow b=\dfrac{\ln (\frac{79}{5})}{9}\\\\\Rightarrow b=0.3066

Insert the value of b

\Rightarrow 5=ae^{0.46}\\\Rightarrow a=5\times 0.6312\\\Rightarrow a=3.156\approx 3.16

So, the function becomes

\Rightarrow f(x)=3.16e^{0.3066b}

\Rightarrow f(3)=3.16e^{0.3066\times 3}\\\Rightarrow f(3)=7.927\approx 7.93

4 0
3 years ago
Read 2 more answers
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