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1 year ago

Using point P, which point would form a line parallel to line AB?

Mathematics

1 answer:

geniusboy [140]1 year ago

8 0

Answer:

(3,2)

Step-by-step explanation:

The equation of the line graphed is

y = 2/3x + 2

Parallel lines have the same slope.

y = mx + b

y = 2/3x + 0 P tells me that the y-intercept is 0

y = 2/3 x Which point would make this true?

Point (3,2) We plug in 3 for x and 2 for y

2 = 2/3(3)

2 = 2 This is a true statement, so the point (3,2) is on the line.

You might be interested in

Why is 4 + (−3) equal to 1?

vladimir2022 [97]

Answer:

2nd option

Step-by-step explanation:

4 + (-3) = 1 because the signs mismatch, something cannot be both positive or negative. When the signs are the same, whether it be both positive or both negative, the answer will always be positive, while if the signs are mismatching the answer will always be negative.

Hope I helped!

7 0

3 years ago

The cost of downloading a book from a certain website is $5.99. The cost of downloading a video is $7.99. Tatum's mom downloads

zaharov [31]

The Answer Is 57.92 But the easiest way to do it is Rounding it

4 0

3 years ago

Read 2 more answers

HELPP!!!!!!!!!!!!!!!!

Anvisha [2.4K]

Answer:

Step-by-step explanation:

We'll take this step by step. The equation is

$8-3\sqrt[5]{x^3}=-7$

Looks like a hard mess to solve but it's actually quite simple, just do one thing at a time. First thing is to subtract 8 from both sides:

$-3\sqrt[5]{x^3}=-15$

The goal is to isolate the term with the x in it, so that means that the -3 has to go. Divide it away on both sides:

$\sqrt[5]{x^3}=5$

Let's rewrite that radical into exponential form:

$x^{\frac{3}{5}}=5$

If we are going to solve for x, we need to multiply both sides by the reciprocal of the power:

$(x^{\frac{3}{5}})^{\frac{5}{3}}=5^{\frac{5}{3}}$

On the left, multiplying the rational exponent by its reciprocal gets rid of the power completely. On the right, let's rewrite that back in radical form to solve it easier:

$x=\sqrt[3]{5^5}$

Let's group that radicad into groups of 3's now to make the simplifying easier:

$x=\sqrt[3]{5^3*5^2}$ because the cubed root of 5 cubed is just 5, so we can pull it out, leaving us with:

$x=5\sqrt[3]{5^2}$ which is the same as:

$x=5\sqrt[3]{25}$

8 0

3 years ago

How do I solve fo A when A/2m=9+H

Neko [114]

Answer:

Step-by-step explanation:

Simply multiply 2m both sides:

A = (9+H)(2m)

Hope this helps!

4 0

3 years ago

Read 2 more answers

What is the future value of 300000 with an interest rate of 17% per annum for 30 days?

Anvisha [2.4K]

$\bf \qquad \textit{Simple Interest Earned Amount}\\\\
A=P(1+rt)\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to& \$300000\\
r=rate\to 17\%\to \frac{17}{100}\to &0.17\\
t=years\to \frac{30}{365}\to &\frac{6}{73}
\end{cases}
\\\\\\
A=300000\left(1+0.17\cdot \frac{6}{73}\right)$

3 0

3 years ago