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alexgriva [62]
1 year ago
7

In the previous lesson, you found the equation of a line to represent the association between latitude and temperature. This is

a mathematical model. Use this mathematical model y = -1.07. + 1 119 predict the average high temperature in September at the following cities that were not included in the original data set: a. Detroit (Lat:42.14) The average high temperature in September will be: OF b. Albuquerque (Lat:35.2) The average high temperature in September will be: OF c. Nome (Lat: 64.5) The average high temperature in September will be: OF d. Peoria, Az (Lat: 33.7) The average high temperature in September will be: OF
Mathematics
1 answer:
user100 [1]1 year ago
7 0

Given an equation of a line to represent the association between latitude and temperature as

y = -1.07x + 1119

\begin{gathered} \text{Let y represents Temperature, and x represents Latitude} \\ \text{Equation of line } \\ y=\text{ -1.07x + 1119} \\ \text{Average temperature in september for } \\ (a)\text{ }Detroit(Lat\colon42.14)\text{ when x =42.14} \\ y\text{ = -1.07(42.14) + 1119} \\ y\text{ = }-45.0898+1119 \\ y\text{ = 1073.91F } \\ (b)\text{ }Albuquerque(Lat\colon35.2)\text{ when x = 35.2} \\ y\text{ = -1.07(35.2) + 1119} \\ y\text{ = -37.664 + 1119} \\ y\text{ = 1081.336}F \\ (c)\text{ }Nome(Lat\colon64.5)\text{ when x = 64.5} \\ y\text{ = -1.07(64.5) + 1119} \\ y\text{ = -69.015 + 1119} \\ y\text{ = 1049.985}F \\ (d)\text{ }Peoria,Az(Lat\colon33.7)\text{ when x = 33.7} \\ y\text{ = -1.07(33.7) + 1119} \\ y\text{ = -36.059+1119} \\ y\text{ = 1082.941}F \end{gathered}

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2 years ago
The brain volumes ?( cm cubed cm3?) of 20 brains have a mean of 1083.9 1083.9 cm cubed cm3 and a standard deviation of 122.2 122
Colt1911 [192]

Answer:

Range: (844.9,1333.7)

A brain volume of 1348.3 cm cubed can be considered significantly high.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 1083.9 cm cubed

Standard Deviation, σ = 122.2 cm cubed

Range rule thumb:

  • This rule state that the the range of data is four times the standard deviation of the data.

\text{Range} = 4\times \sigma = 4\times 122.2 = 488.8

Upper Limit:

\mu + 2\sigma = 1089.3 + 2(122.2) = 1333.7

Lower limit:

\mu - 2\sigma = 1089.3 - 2(122.2) = 844.9

Since, 1348.3 does not lie in the range (844.9,1333.7),  a brain volume of 1348.3 cm cubed can be considered significantly high.

6 0
3 years ago
the difference between two numbers is 10 and their sum is four times the smaller number. find the two numbers
Vanyuwa [196]

Answer:

The smaller number is 5.

The bigger number is 15.

Step-by-step explanation:

Let the smaller number be x and the bigger number be x+10.

x+x+10 = 4x

2x+10 = 4x

10 = 4x-2x

2x = 10

x = 10÷2

  = 5

x+10 = 5+10

       = 15

8 0
3 years ago
Pls help is due tomorrow and if u help i will give u brainliest
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Answer:

Search it up

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6 0
3 years ago
A gambler has a coin which is either fair (equal probability heads or tails) or is biased with a probability of heads equal to 0
yawa3891 [41]

Answer:

(a) 0.1719

(b) 0.3504

Step-by-step explanation:

For every coin the number of heads follows a Binomial distribution and the probability that x of the 10 times are heads is equal to:

P(x)=\frac{n!}{x!(n-x)!}*p^x*(1-p)^{10-x}

Where n is 10 and p is the probability to get head. it means that p is equal to 0.5 for the fair coin and 0.3 for the biased coin

So, for the fair coin, the probability that the number of heads is less than 4 is:

P(x

Where, for example, P(0) and P(1) are calculated as:

P(0)=\frac{10!}{0!(10-0)!}*0.5^0*(1-0.5)^{10-0}=0.0009\\P(1)=\frac{10!}{1!(10-1)!}*0.5^1*(1-0.5)^{10-1}=0.0098

Then, P(x, so there is a probability of 0.1719 that you conclude that the coin is biased given that the coin is fair.

At the same way, for the biased coin, the probability that the number of heads is at least 4 is:

P(x\geq4 )=P(4)+P(5)+P(6)+...+P(10)

Where, for example, P(4) is calculated as:

P(4)=\frac{10!}{4!(10-4)!}*0.3^4*(1-0.3)^{10-4}=0.2001

Then, P(x\geq4 )=0.3504, so there is a probability of 0.3504 that you conclude that the coin is fair given that the coin is biased.

7 0
3 years ago
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