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Answer: I think b but don’t take my word
Step-by-step explanation:
Answer:
The length of the flagpole be 41.2 ft .
Option (A) is correct .
Step-by-step explanation:
As given
The angle looking up at the sun is 70°.
A flagpole casts a shadow of 15 ft .
Now by using the trignometric identity .
BC = 15 ft
tan 70° = 2.75 (Approx)
AB = 2.75 × 15
= 41.2 ft
Therefore the length of the flagpole be 41.2 ft .
Option (A) is correct .
In order to have infinitely many solutions with linear equations/functions, the two equations have to be the same;
In accordance, we can say:
(2p + 7q)x = 4x [1]
(p + 8q)y = 5y [2]
2q - p + 1 = 2 [3]
All we have to do is choose two equations and solve them simultaneously (The simplest ones for what I'm doing and hence the ones I'm going to use are [3] and [2]):
Rearrange in terms of p:
p + 8q = 5 [2]
p = 5 - 8q [2]
p + 2 = 2q + 1 [3]
p = 2q - 1 [3]
Now equate rearranged [2] and [3] and solve for q:
5 - 8q = 2q - 1
10q = 6
q = 6/10 = 3/5 = 0.6
Now, substitute q-value into rearranges equations [2] or [3] to get p:
p = 2(3/5) - 1
p = 6/5 - 1
p = 1/5 = 0.2
Is it not zero ???? ? ? ?
