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frozen [14]
2 years ago
13

A professor grades students on four tests, a term paper, and a final examination. Each test counts as 15% of the course grade. T

he term paper counts as 20% of the course grade. The final examination counts as 20% of the course grade. Alan has test scores of
86, 76, 84, and 80.
Alan received an 80 on his term paper. His final examination score was 90. Use the weighted mean formula to find Alan's average for the course. (Round your answer to one decimal place.)
Mathematics
1 answer:
Dmitry [639]2 years ago
4 0

Answer:

Marilee wants to earn an "A" in a class and needs an overall average of at least Her test grades are 88 , 92,100 , and 80 . The average of her quizzes is 90 and counts as one test grade. The final exam counts as 2.5 test grades. What scores on the final exam would result in Marilee's overall average of 92 or greater? (See Example 9

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Solve the following 3 × 3 system. Enter the coordinates of the solution below.
love history [14]
The system is:

i)    <span>2x – 3y – 2z = 4
ii)    </span><span>x + 3y + 2z = –7
</span>iii)   <span>–4x – 4y – 2z = 10 

the last equation can be simplified, by dividing by -2, 

thus we have:

</span>i)    2x – 3y – 2z = 4
ii)    x + 3y + 2z = –7
iii)   2x +2y +z = -5 


The procedure to solve the system is as follows:

first use any pairs of 2 equations (for example i and ii, i and iii) and equalize them by using one of the variables:

i)    2x – 3y – 2z = 4   
iii)   2x +2y +z = -5 

2x can be written as 3y+2z+4 from the first equation, and -2y-z-5 from the third equation.

Equalize:  

3y+2z+4=-2y-z-5, group common terms:
5y+3z=-9   

similarly, using i and ii, eliminate x:

i)    2x – 3y – 2z = 4
ii)    x + 3y + 2z = –7

multiply the second equation by 2:


i)    2x – 3y – 2z = 4
ii)    2x + 6y + 4z = –14

thus 2x=3y+2z+4 from i and 2x=-6y-4z-14 from ii:

3y+2z+4=-6y-4z-14
9y+6z=-18

So we get 2 equations with variables y and z:

a)   5y+3z=-9 
b)   9y+6z=-18

now the aim of the method is clear: We eliminate one of the variables, creating a system of 2 linear equations with 2 variables, which we can solve by any of the standard methods.

Let's use elimination method, multiply the equation a by -2:

a)   -10y-6z=18 
b)   9y+6z=-18
------------------------    add the equations:

-10y+9y-6z+6z=18-18
-y=0
y=0,

thus :
9y+6z=-18 
0+6z=-18
z=-3

Finally to find x, use any of the equations i, ii or iii:

<span>2x – 3y – 2z = 4 
</span>
<span>2x – 3*0 – 2(-3) = 4

2x+6=4

2x=-2

x=-1

Solution: (x, y, z) = (-1, 0, -3 ) 


Remark: it is always a good attitude to check the answer, because often calculations mistakes can be made:

check by substituting x=-1, y=0, z=-3 in each of the 3 equations and see that for these numbers the equalities hold.</span>
3 0
3 years ago
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Plz solve. plz solve by this Friday thxx ​
Aneli [31]
Answer: About 22%
This is because all of her expenses add up to $800. $175 of those are for her phone and clothes. 175/800 equals about 22 percent. Exact answer is 21.875%
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3 years ago
Solve this root2x-7 =7
Karo-lina-s [1.5K]
-14??
Idek tbh it’s kinda hard
5 0
2 years ago
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PLS HELP: A box is 9 inches wide, 3 inches long, and 12 inches high. It is completely filled with blocks that are each 1 cubie i
LekaFEV [45]

Answer: 304

Step-by-step explanation: first you multiply 9, 3, and 12 which equals 324. Then you subtract 20 from 324 and you get 304.

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3 years ago
Find the optimal solution for the following problem. (Round your answers to 3 decimal places.)
Sphinxa [80]

Answer:

x=2.125

y=0

C=19.125

Step-by-step explanation:

To solve this problem we can use a graphical method, we start first noticing the restrictions x\geq 0 and  y\geq 0, which restricts the solution to be in the positive quadrant. Then we plot the first restriction 8x+10y\leq 17 shown in purple, then we can plot the second one 11x+12y\leq 25 shown in the second plot in green.

The intersection of all three restrictions is plotted in white on the third plot. The intersection points are also marked.

So restrictions intersect on (0,0), (0,1.7) and (2.215,0). Replacing these coordinates on the objective function we get C=0, C=11.9, and C=19.125 respectively. So The function is maximized at (2.215,0) with C=19.125.

3 0
3 years ago
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