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Dima020 [189]
3 years ago
14

Use the graph to answer the question. Between which consecutive years was the increase in the price of oil per barrel greatest?

A. 2004–2005 B. 2009–2010 C. 2010–2011 D. 2007–2008

Mathematics
2 answers:
NARA [144]3 years ago
8 0
D. 2007- 2008:) i think
maxonik [38]3 years ago
6 0
D would be your answer
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Last year Amy eared £18400
beks73 [17]

Answer:

7:23

Step-by-step explanation:

18400/800=23

5600/800=7

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3 years ago
67.77759 rounded to nearest meter
AlekseyPX

Answer:

68

Step-by-step explanation:

0.7 rounds to 1 so add 1 to 67 to get 68

7 0
3 years ago
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The value of Peter's house has risen 20% a year for the last 3 years. If the value of Peter's home 3 years ago was $110,000.00,
IRISSAK [1]
Increase $110,000 by 20% 3 times.

110,000 x 0.2 = 22000
(0.2 is 20% as a decimal, we needed to convert it to multiply it)

So we must add 22000 to 110,000, then take 20% of the new cost, and repeat.

Add them
110,000 + 22000 = 132000

Take 20% of new value
132000 x 0.2 = 26400

Add that
132000 + 26400 = 158400

Take another 20% of that
31680

Add them
158400 + 31680 = 190080

So the value is now $190,080

A much more efficient way to do this would be multiplying 1.2 instead of 0.2, and skipping the adding part, as you already took 100% of it and are adding 20% more.

Hope this helps!
4 0
3 years ago
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Help!! Answer !!! about to run out of time in test!!
Gemiola [76]

\qquad \qquad\huge \underline{\boxed{\sf Answer}}

Here's the solution ~

Let's find the measure of hypotenuse first, by using Pythagoras theorem ;

\qquad \sf  \dashrightarrow \: h {}^{2}  =  {8}^{2}  +  {6}^{2}

\qquad \sf  \dashrightarrow \: h {}^{2}  =  {36}^{}  +  {64}^{}

\qquad \sf  \dashrightarrow \: h {}^{2}  = 100

\qquad \sf  \dashrightarrow \: h {}^{}  =  \sqrt{100}

\qquad \sf  \dashrightarrow \: h {}^{}  =  {10}

Now, let's find the asked values ~

\qquad \sf  \dashrightarrow \:  \sin(x) =  \dfrac{opposite \: side}{hypotenuse}

\qquad \sf  \dashrightarrow \:  \sin(x) =  \dfrac{6}{10}

\qquad \sf  \dashrightarrow \:  \sin(x) =  \dfrac{3}{5}   \: or \: 0.6 \: units

For Cos y :

\qquad \sf  \dashrightarrow \:  \cos(y) =  \dfrac{adjcant \: side}{hypotenuse}

\qquad \sf  \dashrightarrow \:  \cos(y)   = \dfrac{6}{10}

\qquad \sf  \dashrightarrow \:  \cos(y)   = \dfrac{3}{5}  \: or \: 0.6 \: units

As we can see that both sin x and Cos y have equal values, therefore The required relationships is equality.

I.e Sin x = Cos y

Hope it helps ~

3 0
3 years ago
J18 IXL NOW BEFORE TODAYY
Stella [2.4K]

Answer:

heyyyyyyyyy

Step-by-step explanation:

Free pionts thx

4 0
3 years ago
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