Part a: ΔABC≈ΔAPQ
Part b: The line segment PQ corresponds to the line segment BC.
Part c: Angle P in APQ triangle angle equates to angle B.
<h3>Define the term similarity rule of triangles?</h3>
- If two triangles have a similar ratio of adjacent angles and an equal proportion of corresponding sides, they are comparable.
- When two or more objects share the same shape but differ in size, they are referred to as comparable figures.
Part a: line segment PQ parallel to BC; PQ||BC
Thus, ∠ABC =∠APQ AND, ∠ACB=∠AQP
So, by (AA similarity rule)
ΔABC≈ΔAPQ
Part b: The line segment APQ on the triangle corresponds to the line segment BC:
By CPST, line segment PQ on triangle APQ equates to line segment BC (corresponding parts of similar triangle).
Part c: APQ triangle angle equates to angle B:
Angle P on triangle APQ equals angle B via CPST (corresponding parts of similar triangle).
To know more about the similar triangles, here
brainly.com/question/24370649
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