Answer:
Answer:
\{ {{20x+30y=280} \atop {y=4x}} .{
y=4x
20x+30y=280
.
Where xx is the number of small boxes sent and yy is the number of large boxes sent.
Step-by-step explanation:
Let be xx the number of small boxes sent and yy the number of large boxes sent.
Since each small box can hold 20 books (20x20x ), each large box can hold 30 books (30y30y )and altogether can hold a total of 280 books, we can write the following equation to represent this:
20x+30y=28020x+30y=280
According to the information provided in the exercise, there were 4 times as many large boxes sent as small boxes. This can be represented with this equation:
y=4xy=4x
Therefore, the system of equation that be used to determine the number of small boxes sent and the number of large boxes sent, is:
\{ {{20x+30y=280} \atop {y=4x}} .{
y=4x
20x+30y=280
.
Step-by-step explanation:
1 kg = 2.2 pounds
0.45 kg = 1 pounds to see whether it's correct or not we can cross multiply the given equations
multiply 1 kg with 1 pounds and 0.45 kg with 2.2 pounds then check if they are equal
1 × 1 = 2.2 × 0.45
1 = 0.99 as you can see this is not an equality therefore the statement is wrong.
e + 1 13/16 = 2 5/16
subtract 1 13/16 from each side
e = 2 5/16 - 1 13/16
borrow from the 2
e = 1 16/16 + 5 /16 - 1 13/16
e = 1 21/16-1 13/16
e = 1 8 /16
e = 1 1/2
Answer:
$289,169.84 (to the nearest cent)
Step-by-step explanation:
Compound interest is based on the principal amount and the interest that accumulates on it in every period.
Compound Interest = P (1 + r)^n
where P = principal amount, r = annual interest rate (as a decimal), n = term, in years
So for this problem:
P = 185000
r = 1.4 ÷ 100 = 0.015
n = 30
Therefore,
Compound Interest = P (1 + r)^n
= 185000 x (1 + 0.015)^30
= 185000 x (1.015)^30
= 289169.8408...
= $289,169.84 (to the nearest cent)
