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Alchen [17]
1 year ago
10

Greatest common multiple of 12,27

Mathematics
2 answers:
marissa [1.9K]1 year ago
8 0

Answer:

3

Step-by-step explanation:

3x4=12

3x9=27

4 cannot go into 27 without passing 9

Tamiku [17]1 year ago
3 0

Answer:

Factor of 12

= 2 × 2 × 3

Factor of 27

= 3 × 3 × 3

Now ,

CF = 3

HCF = 3

hence...the greatest common multiple of 12 and 27 is 3

...

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The following polynomial is defined on the interval [-2, 2]:
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Using Matlab code for Fourier series to calculate for the function, see the attached

Step-by-step explanation:

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Can you have a negative amplitude?
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No, there can not be negative amplitude because it is just the distance between the max and the midline or the minimum and the midline.

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What is the absolute value of [-2/3]
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4 years ago
A basketball player makes a free throw 82.6% of the time. The player attempts 5 free throws. Use a histogram of the binomial dis
DiKsa [7]

Answer:

The most likely outcome is exactly 4 free throws

Step-by-step explanation:

Given

n = 5 --- attempts

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p = 0.826

Required

A histogram to show the most likely outcome

From the question, we understand that the distribution is binomial.

This is represented as:

P(X = x) = ^nC_x * p^x * (1 - p)^{n-x}

For x = 0 to 5, where x represents the number of free throws; we have:

P(X = x) = ^nC_x * p^x * (1 - p)^{n-x}

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P(X = 0) = ^5C_0 * 0.826^0 * (0.174)^{5}

P(X = 0) = 1 * 1 * 0.000159 \approx 0.0002

P(X = 1) = ^5C_1 * 0.826^1 * (1 - 0.826)^{5-1}

P(X = 1) = ^5C_1 * 0.826^1 * (0.174)^4

P(X = 1) = 5 * 0.826 * 0.000917 \approx 0.0038

P(X = 2) = ^5C_2 * 0.826^2 * (1 - 0.826)^{5-2}

P(X = 2) = ^5C_2 * 0.826^2 * (0.174)^{3}

P(X = 2) = 10 * 0.682 * 0.005268 \approx 0.0359

P(X = 3) = ^5C_3 * 0.826^3 * (1 - 0.826)^{5-3}

P(X = 3) = ^5C_3 * 0.826^3 * (0.174)^2

P(X = 3) = 10 * 0.5636 * 0.030276 \approx 0.1706

P(X = 4) = ^5C_4 * 0.826^4 * (1 - 0.826)^{5-4}

P(X = 4) = 5 * 0.826^4 * (0.174)^1

P(X = 4) = 5 * 0.4655 * 0.174 \approx 0.4050

P(X = 5) = ^5C_5 * 0.826^5 * (1 - 0.826)^{5-5}\\

P(X = 5) = ^5C_5 * 0.826^5 * (0.174)^0

P(X = 5) = 1 * 0.3845 * 1 \approx 0.3845

From the above computations, we have:

P(X = 0)  \approx 0.0002

P(X = 1) \approx 0.0038

P(X = 2)  \approx 0.0359

P(X = 3)  \approx 0.1706

P(X = 4)  \approx 0.4050

P(X = 5) \approx 0.3845

See attachment for histogram

<em>From the histogram, we can see that the most likely outcome is at: x = 4</em>

<em>Because it has the longest vertical bar (0.4050 or 40.5%)</em>

3 0
3 years ago
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