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Gennadij [26K]
2 years ago
10

Someone please help me with this!!! thank you!! (link)

Mathematics
2 answers:
igor_vitrenko [27]2 years ago
7 0
The answer is 50
32 + 1.8(10) = 50
(1.8*10=18)
Naily [24]2 years ago
5 0

F=32+1.8C+10 is the ending equation. Or F=42+1.8C if you want to symplify it.

I hope this is what you were looking for.

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Surface area of a sphere is 615.752 m2, what is the volume of the sphere?
const2013 [10]

B

the volume (V) of a sphere = \frac{4}{3} πr³

We require to know the radius r to calculate the volume

using surface area of a sphere = 4πr² = 615.752

divide both sides by 4π

r² = \frac{615.752}{12.56} = 49.0248...

take the square root of both sides

r = \sqrt{49.0248..} ≈ 7, hence

V= \frac{4}{3} × π × 7³ = 1436.76 m³ → B



8 0
3 years ago
Can someone help me with this?
deff fn [24]

Answer:

the answer is 200

Step-by-step explanation:

4 0
3 years ago
A triangle has one angle measuring 3x degrees. A second angle measures 2x + 20 degrees and the third angle measures 4x -20 degre
Maurinko [17]
All the interior angles of a triangle always add up to 180 degrees.

3x + (2x + 20) + (4x - 20) = 180
3x + 2x + 20 + 4x - 20 = 180
3x + 2x + 4x + 20 - 20 = 180
10x = 180
x = 180/10
Therefore, x = 18
4 0
3 years ago
Read 2 more answers
What number is being factored in this factor tree? <br><br>A.72<br> B.180 <br>C.216<br> D.324
Tatiana [17]

Answer:

not sure if it's ryt but I think it's A

7 0
3 years ago
2. A solar lease customer built up an excess of 6,500 kilowatt hours (kwh) during the summer using his solar
tia_tia [17]

9514 1404 393

Answer:

  a)  E = 6500 -50d

  b)  5000 kWh

  c)  the excess will last only 130 days, not enough for 5 months

Step-by-step explanation:

<u>Given</u>:

  starting excess (E): 6500 kWh

  usage: 50 kWh/day (d)

<u>Find</u>:

  a) E(d)

  b) E(30)

  c) E(150)

<u>Solution</u>:

a) The exces is linearly decreasing with the number of days, so we have ...

  E(d) = 6500 -50d

__

b) After 30 days, the excess remaining is ...

  E(30) = 6500 -50(30) = 5000 . . . . kWh after 30 days

__

c) After 150 days, the excess remaining would be ...

  E(150) = 6500 -50(150) = 6500 -7500 = -1000 . . . . 150 days is beyond the capacity of the system

The supply is not enough to last for 5 months.

3 0
2 years ago
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