1 year ago

Please help with 7-9 they are related to the same circle

1 answer:

3 0

40º

7) In this problem, we can see that both tangent lines to that circle come from the same point O.

So, we can write out the following considering that there is one secant line DO and one tangent line to the circle AO

$\begin{gathered} m\angle1=\frac{1}{2}(160-80) \\ m\angle1=\frac{1}{2}(80) \\ m\angle1=40^{\circ} \end{gathered}$

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jasenka [17]

The answer to this equation is 1/2

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3 years ago

drek231 [11]

I was just on this .

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3 years ago

schepotkina [342]

So lets try to prove it,

So let's consider the function f(x) = x^2.

Since f(x) is a polynomial, then it is continuous on the interval (- infinity, + infinity).

Using the Intermediate Value Theorem,

it would be enough to show that at some point a f(x) is less than 2 and at some point b f(x) is greater than 2. For example, let a = 0 and b = 3.

Therefore, f(0) = 0, which is less than 2, and f(3) = 9, which is greater than 2. Applying IVT to f(x) = x^2 on the interval [0,3}.

Learn more about Intermediate Value Theorem on:

#SPJ4

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1 year ago

Anna [14]

You wouldn’t because 3 is the base number and cannot be simplified anymore

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2 years ago

Rama09 [41]

Answer:

I think it's the 3rd one but tell me if I'm wrong

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2 years ago