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VLD [36.1K]
1 year ago
3

I'm confused with this problem, I forgot how to do these types awhile ago, can you help?

Mathematics
1 answer:
riadik2000 [5.3K]1 year ago
5 0

We have the following inequality given:

9u-34\leq-4(4-3u)

We can start distributing the terms in the rigth and we got:

9u-34\leq-16+12u

Now we can subtrcat 12u in both sides of the inequality and we got:

-3u-34\leq-16

Finally we can add 34 in both sides of the inequalty and we got:

-3u\leq18

We can multiply both sides of the inequality by -1 and we got this:

3u\ge-18

Finally dividing by 3 we got:

u\ge-6

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Help picture below problem 10
DedPeter [7]

<u>Solution</u><u> </u><u>:</u><u>-</u>

Here, we have been given that lines f and g are parallel. Thus, the angle measuring 135° and ∠2 are vertically opposite angles.

And we know that vertically opposite angles measure same. Thus,

∠2 = 135°

And,

∠2 + ∠6 = 180° ( Co - interior angles sum up to 180° )

135° + ∠6 = 180°

∠6 = 180° - 135°

∠6 = 45°

Hope that helps :)

4 0
3 years ago
Help me please<br> Idk what to do
Ber [7]

Answer:

x=36

Step-by-step explanation:

First rewrite equation then multiply each side by 36. 9x-36=4x+144.

then move the variable 9x-4x+36=144. Next subtract 9x and 4x ...5x=144+36.... 5x=180. Lastly you divide 180÷5 this your answer x=36

4 0
3 years ago
What is the equation of a line that is perpendicular to −x+3y=9 and passes through the point (−3, 2) ?
vekshin1

The equation of line that is perpendicular to the line -x+3y =9  and passes through the point \left({-3,2}\right)  is \boxed{{\mathbf{y=-3x-7}}} .

Further explanation:

It is given that the equation of line is -x+3y =9  and passes through point \left({-3,2}\right) .

Rewrite the given equation -x+3y =9  as follows:

\begin{aligned}-x+3y&=9\\3y&=9+x\\y&=\frac{9}{3}+\frac{1}{3}x\\y&=\frac{1}{3}x+3\\\end{aligned}

Now, compare the obtained equation of line y=\frac{1}{3}x+3  with the standard equation of line y=mx+b .

\begin{aligned}m&=\frac{1}{3}\\b&=3\\\end{aligned}

Therefore, the slope is \frac{1}{3} .

It is given that both lines are perpendicular to each other so the product of slope must be equal to -1 .

{m_1}\cdot {m_2}=-1                                                          …… (1)

Substitute \frac{1}{3}  for {m_1}  in equation (1) to obtain the value of slope {m_2} .

\begin{aligned}\frac{1}{3}\cdot{m_2}&=-1\\{m_2}&=-3\\\end{aligned}

Therefore, the slope is -3 .

It is given that the line passes through point \left({-3,2}\right) .

The point-slope form of the equation of a line with slope m  passes through point \left({{x_1},{y_1}}\right) is represented as follows:

y-{y_1}=m\left({x-{x_1}}\right)                                      …… (2)

Substitute -3  for {x_1} , 2  for {y_1}  and -3  for m  in equation (2) to obtain the equation of line.

\begin{aligned}y-2&=-3\left({x-\left({-3}\right)}\right)\\y-2&=-3\left({x+3}\right)\\y&=-3x-9+2\\y&=-3x-7\\\end{aligned}

Therefore, the equation of line is y=-3x-7 .

Thus, the equation of line that is perpendicular to the line -x+3y=9  and passes through the point \left({-3,2}\right)  is \boxed{{\mathbf{y=-3x-7}}} .

Learn more:

1. Which classification best describes the following system of equations? <u>brainly.com/question/9045597 </u>

2. What is the value of x  in the equation x-y=30  when y=15 ? <u>brainly.com/question/3965451 </u>

3. What are the values of x? <u>brainly.com/question/2093003</u>

Answer Details:

Grade: Junior High School

Subject: Mathematics

Chapter: Coordinate Geometry

Keywords: Coordinate Geometry, linear equation, system of linear equations in two variables, variables, mathematics, equation of line, line, passes through point.

6 0
4 years ago
Read 2 more answers
W varies directly as x and inversely as the square of y
MArishka [77]

Answer:

w=kx/y^2

Step-by-step explanation:

7 0
3 years ago
You are standing 25 feet from the base of a flagpole.The angle of elevation to the top of the flagpole is 40°.What is the height
liraira [26]

Answer: the height of the flagpole is 21 ft

Step-by-step explanation:

Since the angle of elevation to the top of the flagpole is 40°, a right angle triangle is formed. The height of the flagpole represents the opposite side of the right angle triangle. Your distance from the base of the flagpole represents the adjacent side of the right angle triangle. Therefore, to determine the height of the flagpole, x ,we would apply the tangent trigonometric ratio which is expressed as

Tan θ = opposite side/adjacent side

Tan 40 = x/25

x = 25tan40 = 25 × 0.8391

x = 20.98

x = 21.0 ft to the nearest tenth.

6 0
3 years ago
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