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1 year ago

How to use a 12th grade calculator

Mathematics

1 answer:

kondaur [170]1 year ago

4 0

Click random buttons until you figure it out, or even ask a parent or teacher

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) Set up a double integral for calculating the flux of F=3xi+yj+zk through the part of the surface z=−5x−2y+2 above the triangle

Fynjy0 [20]

The surface (call it $S$ ) is a triangle with vertices at the points

$x=0,y=0\implies z=2\implies(0,0,2)$

$x=0,y=2\implies z=-2\implies(0,2,-2)$

$x=2,y=0\implies z=-8\implies(2,0,-8)$

Parameterize $S$ by

$\vec s(u,v)=(1-v)(2,0,-8)+v\bigg((1-u)(0,2,-2)+u(0,0,2)\bigg)=(2-2v,2v-2uv,-8+6v+4uv)$

with $0\le u\le1$ and $0\le v\le1$ . Take the normal vector to $S$ to be

$\vec s_v\times\vec s_u=(20v,8v,4v)$

Then the flux of $\vec F$ across $S$ is

$\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^1\int_0^1(6-6v,2v-2uv,-8+6v+4uv)\cdot(20v,8v,4v)\,\mathrm du\,\mathrm dv$

$=\displaystyle8\int_0^1\int_0^1(11v-10v^2)\,\mathrm du\,\mathrm dv=\boxed{\frac{52}3}$

8 0

3 years ago

Does anyone know how to find the side length of this square.if so then, i will mark brainlist.

kvv77 [185]

Hello!

To find the side length you use the equation

$a = \sqrt{2} \frac{d}{2}$

a is side length
d is diagonal

Put in the number we know

$a = \sqrt{2} * \frac{27}{2}$

Divide

$a = \sqrt{2} * 13.5$

Multiply

a = 19.091

The answer is 19.09

Hope this helps!

8 0

3 years ago

Urgent!!! Will give thanks and branliest!

agasfer [191]

Okay so, togo flies 30 miles in 3/5 of an hour with the wind.togo flies 30 miles in 5/6 of an hour against the wind. his rate of speed with the wind was 30 / (3/5) = 30*5/3 = 150/3 = 50 mph.his rate of speed against the wind was 30 / (5/6) = 30*6/5 = 6*6 = 36 mph.3/5 of an hour times 50 mph = 30 miles.
5/6 of an hour times 36 mph = 30 miles.mph looks good.
going he was with the wind.
his rate of speed then was the airplane speed plus the wind speed.coming back he was against the wind.his rate of speed then was the airplane speed minus the wind speed.-----50 mph = A + W36 mph = A - W-----looks like A + W - (A - W) should equal 50 - 36.removing parentheses, equation becomesA + W - A + W = 14.
combining like terms, the equation becomes2*W = 14.dividing both sides by 2, equation becomesW = 7.if W = 7, then A can be found as follows:50 = A + 7A = 43.likewise,36 = A - 7A = 43.since the airplane speed is the same, it looks like the answer is good.solving in the original equations, we get3/5 * (43 + 7) = 303/5 * 50- = 3030 = 30good.-----5/6 * (43 - 7) = 305/6 * 36 = 3030 = 30good.
answer is W = 7 and A = 43.

8 0

3 years ago

Please help asap 15 pts

liq [111]

= -9x - 12 - 4x

= - 13x - 12

Answer

a) - 13x - 12

6 0

3 years ago

Read 2 more answers

3250-1250=1500+2(1250-500) is this true

exis [7]

Answer:

Its false because

Step-by-step explanation:

3250-1250=1500+2.(1250-500)

2000 = 1500 + 2 . 750

2000 = 1500 + 1500

2000 != 3000

Obviously 2000 isnt the same of 3000

5 0

3 years ago

Read 2 more answers