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Firlakuza [10]
11 months ago
13

The total amount spent by some number of people on clothing and footwear In the years 2000-2009 can be modeled by the quadratic

function. Where x=0 represents January 1, 2000, x=1 represents January 1, 2001, and so on, and f(x) is in billions of dollars. According to the model, in what year during this period was the amount of clothing and footwear a maximum In the year (blank) , (blank) billion was spent on clothing and footwear.

Mathematics
1 answer:
FinnZ [79.3K]11 months ago
4 0

For this problem, we are given a quadratic equation that models the total amount spent on clothing and footwear in the years 2000-2009. We need to use the model to determine the maximum amount spent during the period.

The equation is shown below:

f(x)=-4.462x^2+71.54x+97.44

Since the leading term is negative, the vertex of this function will represent an absolute maximum value. Therefore we can determine the vertex to answer the problem, the vertex's coordinates are given below:

\begin{gathered} x_{max}=\frac{-b}{2a}\\ \\ y_{max}=f(x_{max}) \end{gathered}

Then we have:

\begin{gathered} x_{max}=\frac{-71.54}{2\cdot(-4.462)}=8.017\\ \\ y_{max}=-4.462\cdot(8.017)^2+71.54\cdot(8.017)+97.44=384.2 \end{gathered}

In the year 2008, 384 billion was spent on clothing and footwear.

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Step-by-step explanation:

You simply take 33.5 and add .085 to 33.5 get your answer.then subtract .085 from 33.5

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How would I find all real solutions in x^4/3 -10^2/3 +21= 0
Oxana [17]

Answer:

Step-by-step explanation:

This equation looks complicated.We have to make it easier

let's say x^2/3 = t  and  x^4/3 = t^2

     

      t^2-10t+21=0   [ we can factorize this equation as a (t-3)(t-7) ]

     

      (t-3)(t-7)=0  [ that means , t can be 3 or 7 ]

But don't forget we have to find x not t so,

   t=x^2/3=3     ∛ x^2 = 3       x^2 = 9    x=3 or x= -3

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What is 2/5 as a decimal
Natali5045456 [20]

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3 years ago
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Please help me if you can. Please also write how you got the answer thank you.
vaieri [72.5K]

Answer:

The three numbers are 341, 342, and 343

Step-by-step explanation:

We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 1026. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 1026

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 1026

3X + 3 = 1026

3X + 3 - 3 = 1026 - 3

3X = 1023

3X/3 = 1023/3

X = 341

Which means that the first number is 341, the second number is 341 + 1 and the third number is 341 + 2. Therefore, three consecutive integers that add up to 1026 are 341, 342, and 343.

341 + 342 + 343 = 1026

We know our answer is correct because 341 + 342 + 343 equals 1026 as displayed above.

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