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Greeley [361]
3 years ago
12

Where my crybabies at?????????

Mathematics
1 answer:
vaieri [72.5K]3 years ago
8 0
Idk honestly, haven’t cryied since I ate a warhead
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3 years ago
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Use the definition of continuity and the properties of limit to show that the function f(x)=x sqrtx/ (x-6)^2 is continuous at x=
jasenka [17]

Answer:

The function \\ f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}} is continuous at x = 36.

Step-by-step explanation:

We need to follow the following steps:

The function is:

\\ f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}}

The function is continuous at point x=36 if:

  1. The function \\ f(x) exists at x=36.
  2. The limit on both sides of 36 exists.
  3. The value of the function at x=36 is the same as the value of the limit of the function at x = 36.

Therefore:

The value of the function at x = 36 is:

\\ f(36) = \frac{36*\sqrt{36}}{(36-6)^{2}}

\\ f(36) = \frac{36*6}{900} = \frac{6}{25}

The limit of the \\ f(x) is the same at both sides of x=36, that is, the evaluation of the limit for values coming below x = 36, or 33, 34, 35.5, 35.9, 35.99999 is the same that the limit for values coming above x = 36, or 38, 37, 36.5, 36.1, 36.01, 36.001, 36.0001, etc.

For this case:

\\ lim_{x \to 36} f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}}

\\ \lim_{x \to 36} f(x) = \frac{6}{25}

Since

\\ f(36) = \frac{6}{25}

And

\\ \lim_{x \to 36} f(x) = \frac{6}{25}

Then, the function \\ f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}} is continuous at x = 36.

8 0
3 years ago
I need major help thank you
telo118 [61]
D is the answer hope this helped but if it’s wrong i am generally sorry
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3 years ago
Laura cuts 64 inches of ribbon into two parts and give her mom one part. Laura's part is 28 inches long. Her mom cuts her ribbon
Korvikt [17]
6x+28=64\\\\6x=36\ /:6\\\\x=6
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Select the linear equation represented in the graph.
AleksAgata [21]

Answer:

y = \frac{1}{2} x + 3

Step-by-step explanation:

use y = mx + b

slope(m) = \frac{1}{2}

y-intercept(b) = 3

so,

y = \frac{1}{2} x + 3

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