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noname [10]
1 year ago
11

If xx and y vary directly and y is 21 when x is 7, find y when x is 5

Mathematics
2 answers:
Sedaia [141]1 year ago
6 0

Answer: y = 15

Step-by-step explanation:  

8_murik_8 [283]1 year ago
3 0

Answer:

y = 15

Step-by-step explanation:

We need to solve for k

y = x

21 = 7k  Divide both sides by 7 to solve for k

3 = k

y = xk

y = 5(3)

y = 15

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What can a denominator never be?

0

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so, what x values make our denominator 0?

to figure this out, we need to set (x-1)(x-2)=0

now we split and solve.

x - 1 = 0 \\ x - 2 = 0
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but, x can be every other number and it does, so the answer is
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7 0
3 years ago
Write the quadratic function f(x) = x2 - 5x + 3 in vertex form. Complete the square to determine the maximum or minimum value of
enyata [817]

Answer:

a). Vertex form f the function f(x) = (x - 2.5)²+3.25

b). Maximum value of the function is (-3)

Step-by-step explanation:

a). f(x) = x² - 5x + 3

we have to write this function in the vertex form.

f(x) = x² - 2(2.5)x + 3

    = [(1)²x²- 2(2.5)x + (2.5)²-(2.5)²] + 3

    = (x - 2.5)²- 6.25 + 3

    = (x - 2.5)² - 3.25

So the vertex for of the function is

f(x) = (x - 2.5)² - 3.25

b). Given quadratic function f(x) = -x² - 6x + 6 is in the standard form of f(x) = ax² + bx + c.

By comparing the coefficients of both the functions,

a = -1, b = 6 and c = 6

Here the value of a is negative, therefore, the given parabola is opening downwards.

And the maximum will occur at

x=-\frac{b}{2a}

When we plug in the values,

x=-\frac{6}{2(-1)}

x = 3

Now to get the value of maximum of the function we will get the value of f(3).

f(3) = -(3)²- 6(3) + 6

f(3) = 9 - 18 + 6

f(3) = -3

Therefore, maximum value of the quadratic function is (-3).

4 0
3 years ago
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Answer:

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Step-by-step explanation:


4 0
3 years ago
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d1i1m1o1n [39]

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

Just trust me its right

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