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Jobisdone [24]
3 years ago
7

The length of a rectangle is 2 inches more than

Mathematics
1 answer:
amm18123 years ago
3 0

Answer:334

Step-by-step explanation:

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Monica [59]
The answer to this question is b
7 0
3 years ago
The triangular-shaped bases of a prism are 24 cm in length and have a height of 35 cm. Each side is 37 cm. The height of the pri
Savatey [412]

Answer:

The surface area of Triangular base Prism = 3682 cm²

Step-by-step explanation:

Given in question as :

For a Triangular base prism ,

The base of  prism (b) = 24 cm

The height of prism (l) = 29 cm

Each side length (s) = 37 cm

The height of base triangle ( h ) = 35 cm

Hence , we know that The surface area of Triangular base prism is

 = (b×h) + (2×l×s) + (l×b)

 = (24×35) + (2×29×37) + (29×24)

 = (840) + (2146) + (696)

 = 3682  cm²

Hence The surface area of Triangular base Prism is 3682 cm²  Answer

3 0
3 years ago
Find the general solution of x'1 = 3x1 - x2 + et, x'2 = x1.
Ann [662]
Note that if {x_2}'=x_1, then {x_2}''={x_1}', and so we can collapse the system of ODEs into a linear ODE:

{x_2}''=3{x_2}'-x_2+e^t
{x_2}''-3{x_2}'+x_2=e^t

which is a pretty standard linear ODE with constant coefficients. We have characteristic equation

r^2-3r+1=\left(r-\dfrac{3+\sqrt5}2\right)\left(r+\dfrac{3+\sqrt5}2\right)=0

so that the characteristic solution is

{x_2}_C=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}

Now let's suppose the particular solution is {x_2}_p=ae^t. Then

{x_2}_p={{x_2}_p}'={{x_2}_p}''=ae^t

and so

ae^t-3ae^t+ae^t=-ae^t=e^t\implies a=-1

Thus the general solution for x_2 is

x_2=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}-e^t

and you can find the solution x_1 by simply differentiating x_2.
7 0
3 years ago
Help with these please
JulsSmile [24]
Do you want the answer?
4 0
3 years ago
Help... It's homework, I need ur Help :""""")​
pochemuha

Answer:

112

Step-by-step explanation:

the formula for area is length times width,so in this case 14×8 = the area

6 0
3 years ago
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