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1 year ago

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if a dealer buys a car from a manufacturer for $20,480 and sells it for $26,808...what is his markup? rounded to the nearest ten

th as needed...as an integer or decimal

1 answer:

yulyashka [42]1 year ago

4 0

To find the markup, substract the price at which the car was bought from the price at which the car was sold:

$26,808-20,480=6328$

To find the markup as a percentage from the original price, set 20,480 to be equal to 100%. If <em>x%</em> represents 6328, then:

$\begin{gathered} \frac{x}{6328}=\frac{100}{20,480} \\ \Rightarrow x=\frac{100\times6328}{20,480}=30.898\ldots \end{gathered}$

To the nearest tenth, 30.898... = 30.9.

Therefore, the markup is equal to 30.9%.

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$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&124&-54&77&:-82\end{array}\right]$

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$\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&1&-\frac{663}{254} &:-\frac{1690}{254} \end{array}\right]$

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$r_{1}$ ↔ $r_{1} - 4r_{3}$ , $r_{2}$ ↔ $r_{2} + \frac{1}{7} r_{3}$

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