The speed of the plane after it encounters the wind is C.285mph
<h3>How to calculate the speed of the plane when it encounters the wind?</h3>
Since the plane takes off from an airport on a bearing of 270° and travels at a speed of 320 mph it's velocity is v = (320cos270°)i + (320sin270°)j
= (320 × 0)i + (320 × -1)j
= 0i - 320j
= - 320j mph
Also, the plane encounters a 35 mph wind blowing directly north. The velocity of the wind is v' = 35j mph
So, the velocity of the plane after it encounters the wind is the resultant velocity, V = v + v'
= -320j mph + 35j mph
= -285j mph
So, the speed of the plane after it encounters the wind is the magnitude of V = |-285j| mph
= 285 mph
So, the speed of the plane after it encounters the wind is C.285mph
Learn more about speed of plane here:
brainly.com/question/3387746
#SPJ1
Tan M = opposite / adjacent
tan M = KL / KM
tan M = 15/8
Letter C
Answer:
30 ,345,986
Step-by-step explanation:
Answer:
Slope=4/5
Step-by-step explanation:
This is the formula to find the slope of lines:
y2-y1/x2-x1 (look it up to learn more)
9-1/1+9
8/10
4/5
The slope is 4/5
Hope this helps :)
271 rounded is 300, and 425 rounded is 400, so you could estimate the sum by adding 300 and 400, which equals 700.
