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1 year ago

Find the measure of angle b. A. 38 B. 67 C. 75 D. 105

Mathematics

2 answers:

MrMuchimi1 year ago

8 0

Answer:

it’s B

Step-by-step explanation:

just took the test

Shalnov [3]1 year ago

6 0

Answer:

D.105

Step-by-step explanation:

sum of measures of the three angles equal 180

therefore measure of angle B equal 180-(52+23)=105 degree

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Someone pls show me

vlada-n [284]

Answer:

x = 4

Step-by-step explanation:

An exterior angle of a triangle is equal to the sum of the remote interior angles.

18x +5 = (46) +(-1 +8x)

10x = 40 . . . . . . . . . . . . . subtract (5+8x) from both sides, simplify

x = 4 . . . . . . divide by 10

<em>Additional comment</em>

The exterior angle is (18)(4) +5 = 77°. The marked unknown interior angle is -1+(8)(4) = 31°. The sum of the two remote interior angles is 46°+31° = 77°. The unmarked interior angle is 180°-77° = 103°.

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2 years ago

The probability of pulling an orange is 2 out of 5 if I 20 times how many of them would be orange

telo118 [61]

The answer would be 8.

4 0

3 years ago

10 hours to 6 hours percent of change

Novay_Z [31]

60%

I pretty sure this is right

4 0

3 years ago

Read 2 more answers

A bar of gold has a volume of 722 cubic centimeters and weighs 13.949 kilograms. What's its density in grams per cubic centimete

Ahat [919]

Answer:

The density of the bar of gold is 19.32 grams per cubic centimeter .

Step-by-step explanation:

Formula

$Density = \frac{Mass}{Volume}$

As given

A bar of gold has a volume of 722 cubic centimeters and weighs 13.949 kilograms.

As 1 kilogram = 1000 gram

Than convert 13.949 kilograms into grams.

13.949 kilograms = 13.949 × 1000 grams

= 13949 grams

Mass = 13949 grams

Volume = 722 cubic centimeter

As put in the formula

$Density = \frac{13949}{722}$

Density = 19.32 grams per cubic centimeter (Approx)

Therefore the density of the bar of gold is 19.32 grams per cubic centimeter .

8 0

3 years ago

19. A quadratic equation is shown below.

victus00 [196]

Answer:

$\{\sqrt b, -\sqrt b\}$

Step-by-step explanation:

Given

$a^2 - b = 0$

Required

Determine the solution

Since b is a perfect square, the equation can be expressed as:

$a^2 - (\sqrt b)^2 = 0$

Apply difference of two squares:

$(a - \sqrt b)(a + \sqrt b) = 0$

Split:

$(a - \sqrt b)= 0 \ or\ (a + \sqrt b) = 0$

Remove brackets:

$a - \sqrt b= 0 \ or\ a + \sqrt b = 0$

Make a the subject in both equations

$a =\sqrt b \ or\ a =-\sqrt b$

The solution can be represented as:

$\{\sqrt b, -\sqrt b\}$

6 0

3 years ago