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Umnica [9.8K]
1 year ago
13

A tv show had 4.4 x 106 viewers in the first week and 3.1 x 106 viewers in the second week. determine the average number of view

ers over the two weeks and write the final answer in scientific notation.
Mathematics
1 answer:
rosijanka [135]1 year ago
5 0

The average number of viewers over the two weeks are 3.75 X 10^6

A tv show had 4.4 x 10^6 viewers in the first week

and 3.1 x 10^6 viewers in the second week.

What is average number ?

This is the arithmetic mean, and is calculated by adding a group of numbers and then dividing by the count of those numbers.

To find the average number of viewers over the two weeks

Remove the decimal point.

4.4 x 10^6 write like this 4400000

Similarly, 3.1 x 10^6 write like this 3100000

Now, Solving the question

Therefore, the average will be  

4400000 + 3100000

= 7500000/2

=3750000

=3.75 X 10^6

and3.75 x 10^6

Thus , the average number of viewers over the two week  3.75 x 10^6

Learn more about Average Number at:

brainly.com/question/28376264

#SPJ4

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Answer:

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Step-by-step explanation:

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<u>Given</u>:

The quadratic equation is x^{2}=-5 x-3

We need to determine the solutions of the quadratic equation.

<u>Solution</u>:

Let us solve the equation to determine the value of x.

Adding both sides of the equation by 5x and 3, we get;

x^{2}+5 x+3=0

The solution of the equation can be determined using quadratic formula.

Thus, we get;

x=\frac{-5 \pm \sqrt{5^{2}-4 \cdot 1 \cdot 3}}{2 \cdot 1}

x=\frac{-5 \pm \sqrt{25-12}}{2 }

x=\frac{-5 \pm \sqrt{13}}{2 }

Thus, the two roots of the equation are x=\frac{-5 + \sqrt{13}}{2 } and x=\frac{-5- \sqrt{13}}{2 }

Hence, the solutions of the equation are x=\frac{-5 + \sqrt{13}}{2 } and x=\frac{-5- \sqrt{13}}{2 }

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3 years ago
Read 2 more answers
Find number a and k so that x-2 is afactor<br>OF F(x)=x4-2ax tax-<br>X+k and F(-1)=3​
Slav-nsk [51]

Question:

Find numbers a and k so that x-2 is a factor of

f(x)=x^4-2ax^3+ax^2- x+k

and

f(-1)=3

Answer:

k = -2 and a=1

Step-by-step explanation:

Given

f(x)=x^4-2ax^3+ax^2- x+k

Factor:\ x - 4

f(-1)=3

Required

Find a and k

For f(-1)=3

Substitute -1 for x

f(x)=x^4-2ax^3+ax^2- x+k

f(-1) = (-1)^4 - 2a *(-1)^3 + a*(-1)^2 - (-1) + k

f(-1) = 1 - 2a *-1 + a*1 +1 + k

f(-1) = 1 +2a + a +1 + k

f(-1) = 2 +3a + k

Substitute 3 for f(-1)

3 = 2 +3a + k

Collect Like Terms

3 - 2 = 3a + k

1 = 3a + k

Also:

If x - 2 is a factor, then

f(2) = 0

Substitute 2 for x and 0 for f(x)

f(x)=x^4-2ax^3+ax^2- x+k

0 = 2^4 - 2a * 2^3 + a * 2^2 - 2 + k

0 = 16 - 2a * 8 + a * 4 - 2 + k

0 = 16 - 16a + 4a - 2 + k

0 = 16 - 12a - 2 + k

Collect Like Terms

2 - 16 = - 12a + k

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k = 12a - 14

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a = \frac{15}{15}

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k = 12 * 1 - 14

k = 12 - 14

k = -2

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Answer:

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Now, divide both sides again by r²:

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Answer:

<em>Step-by-step explanation:</em>

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