7/6
The slope of the equation in the form y=Mx+c is m
Parallel lines have Same gradient
Which makes gradient 7/6
Please mark as brainliest
To find the area of a parallelogram, multiply the base by the height. the formula is: A= Base times height where B is the base, and H is the height, and * means multiply. the base and height of a parallelogram must be perpendicular
Domain: {-5, 7}
Range: {-9, 4, 8}
<u>Answer-</u>
<em>The amount will be </em><em>$8944.62</em><em> after 5 years.</em>
<u>Solution-</u>
We know that,
![\text{FV of annuity}=P[\dfrac{(1+r)^n-1}{r}]](https://tex.z-dn.net/?f=%5Ctext%7BFV%20of%20annuity%7D%3DP%5B%5Cdfrac%7B%281%2Br%29%5En-1%7D%7Br%7D%5D)
Where,
P = Payment = $50 monthly
r = rate of interest compounded monthly= 
n = number of period = 5 years = 5×12 = 60 months
Putting the values in the formula,
![\text{FV of annuity}=50[\dfrac{(1+0.0325)^{60}-1}{0.0325}]](https://tex.z-dn.net/?f=%5Ctext%7BFV%20of%20annuity%7D%3D50%5B%5Cdfrac%7B%281%2B0.0325%29%5E%7B60%7D-1%7D%7B0.0325%7D%5D)
![=50[\dfrac{(1.0325)^{60}-1}{0.0325}]](https://tex.z-dn.net/?f=%3D50%5B%5Cdfrac%7B%281.0325%29%5E%7B60%7D-1%7D%7B0.0325%7D%5D)
![=50[\dfrac{6.8140-1}{0.0325}]](https://tex.z-dn.net/?f=%3D50%5B%5Cdfrac%7B6.8140-1%7D%7B0.0325%7D%5D)
![=50[\dfrac{5.8140}{0.0325}]](https://tex.z-dn.net/?f=%3D50%5B%5Cdfrac%7B5.8140%7D%7B0.0325%7D%5D)


Therefore, the amount will be $8944.62 after 5 years.
Answer:
No, the on-time rate of 74% is not correct.
Solution:
As per the question:
Sample size, n = 60
The proportion of the population, P' = 74% = 0.74
q' = 1 - 0.74 = 0.26
We need to find the probability that out of 60 trains, 38 or lesser trains arrive on time.
Now,
The proportion of the given sample, p = 
Therefore, the probability is given by:
![P(p\leq 0.634) = [\frac{p - P'}{\sqrt{\frac{P'q'}{n}}}]\leq [\frac{0.634 - 0.74}{\sqrt{\frac{0.74\times 0.26}{60}}}]](https://tex.z-dn.net/?f=P%28p%5Cleq%200.634%29%20%3D%20%5B%5Cfrac%7Bp%20-%20P%27%7D%7B%5Csqrt%7B%5Cfrac%7BP%27q%27%7D%7Bn%7D%7D%7D%5D%5Cleq%20%5B%5Cfrac%7B0.634%20-%200.74%7D%7B%5Csqrt%7B%5Cfrac%7B0.74%5Ctimes%200.26%7D%7B60%7D%7D%7D%5D)
P![(p\leq 0.634) = P[z\leq -1.87188]](https://tex.z-dn.net/?f=%28p%5Cleq%200.634%29%20%3D%20P%5Bz%5Cleq%20-1.87188%5D)
P![(p\leq 0.634) = P[z\leq -1.87] = 0.0298](https://tex.z-dn.net/?f=%28p%5Cleq%200.634%29%20%3D%20P%5Bz%5Cleq%20-1.87%5D%20%3D%200.0298)
Therefore, Probability of the 38 or lesser trains out of 60 trains to be on time is 0.0298 or 2.98 %
Thus the on-time rate of 74% is incorrect.