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Ber [7]
1 year ago
12

In the figure, PQ is parallel to RS. The length of RP is 5cm; the length of PT is 30cm; the length of QT is 60cm. What is the le

ngth of SQ?○A.10cm○B.6cm○C.2cm○D.20cm

Mathematics
1 answer:
rjkz [21]1 year ago
3 0

The triangles PTQ and RTS are similar; so the ratios of corresponding sides are equal.

Let us denote the unknown length SQ as x.

We could make the following similarity relation;

\begin{gathered} \frac{30}{30+5}=\frac{60}{60+x} \\  \end{gathered}

Cross multiply to obtain;

\begin{gathered} 30(60+x)=60(35) \\ 1800+30x=2100 \\ \text{collect like terms} \\ 30x=2100-1800 \\ 30x=300 \\ \text{divide both sides by 30} \\ \frac{30x}{30}=\frac{300}{30} \end{gathered}

Therefore;

x=10\operatorname{cm}

Therefore, the answer is option A

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The weights of a certain dog breed are approximately normally distributed with a mean of 49 pounds, and a standard deviation of
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a. 74.86%

b. 50%

c. 50%

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with a mean of 49 pounds, and a standard deviation of 6 pounds.

This means that \mu = 49, \sigma = 6

a. Find the percentage of dogs of this breed that weigh less than 53 pounds.

The proportion is the p-value of Z when X = 53. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{53 - 49}{6}

Z = 0.67

Z = 0.67 has a p-value of 0.7486.

0.7486*100% = 74.86%, which is percentage of dogs of this breed that weigh less than 53 pounds.

b. Find the percentage of dogs of this breed that weigh less than 49 pounds.

p-value of Z when X = 49, so:

Z = \frac{X - \mu}{\sigma}

Z = \frac{49 - 49}{6}

Z = 0

Z = 0 has a p-value of 0.5

0.5 = 50% of dogs of this breed that weigh less than 49 pounds.

c. Find the percentage of dogs of this breed that weigh more than 49 pounds.

1 subtracted by the p-value of Z when X = 49, so:

Z = \frac{X - \mu}{\sigma}

Z = \frac{49 - 49}{6}

Z = 0

Z = 0 has a p-value of 0.5.

1 - 0.5 = 0.5 = 50% of dogs of this breed that weigh more than 49 pounds.

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Answer:

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