What is the distance around a triangle that has sides measuring 2 1/8, 3 1/2, and 2 1/2 feet?

Mathematics

1 answer:

Mashcka [7]2 years ago

3 0

Perimeter = 2 1/8 + 3 1/2 + 2 1/2 = 7 (1 + 4 + 4)/8 = 7 9/8 = 8 1/8

You might be interested in

The music store sold 12 trumoets and 19 clarinets last month. If clariners sell for $139.95 and the store made $4,578.45 from sa

Kamila [148]

Answer:

$159.95

Step-by-step explanation:

Let price of trumphet be defined by $x$

price of clarinet = $139.95

Number of clarinets sold = 19

Earning through clarinets' sale = $19*139.95 = 2659.05$

Total earning of store = $4578.45

Earning through trumphets' sale = $4578.45 - 2659.05 = 1919.40$

price of one trumohet = $\frac{1919.40}{12} = 159.95$

price of clarinet = $159.95

7 0

3 years ago

A large corporation starts at time t = 0 to invest part of its receipts continuously at a rate of P dollars per year in a fund f

Andrews [41]

Answer:

$A = \frac{P}{r}\left( e^{rt} -1 \right)$

Step-by-step explanation:

This is <em>a separable differential equation</em>. Rearranging terms in the equation gives

$\frac{dA}{rA+P} = dt$

Integration on both sides gives

$\int \frac{dA}{rA+P} = \int dt$

where $c$ is a constant of integration.

The steps for solving the integral on the right hand side are presented below.

$\int \frac{dA}{rA+P} = \begin{vmatrix} rA+P = m \implies rdA = dm\end{vmatrix} \\\\\phantom{\int \frac{dA}{rA+P} } = \int \frac{1}{m} \frac{1}{r} \, dm \\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \int \frac{1}{m} \, dm\\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |m| + c \\\\&\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |rA+P| +c$