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qaws [65]
1 year ago
13

A local health clinic surveys its patients about their waterdrinking habits. It found the data is normally distributed,the mean

amount of water consumed daily is 62 ounces, andthe standard deviation is 5.2. How much water, in ounces,do approximately 95% of the patients drink each day?A: 56.8 to 67.2B: 54.2 to 69.8C: 51.6 to 72.4D: 41.2 to 62.0
Mathematics
1 answer:
satela [25.4K]1 year ago
3 0

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data:

water drinking habits:

mean = 62 ounces

standard deviation = 5.2 ounces

Step 02:

normally distribution:

95% ===> 2 SD

(62 + 5.2 + 5.2) ounces = 72.4 ounces ==> + 2 SD

(62 - 5.2 - 5.2) ounces = 51.6 ounces ==> - 2 SD

The answer is:

51.6 ounces - 72.4 ounces

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Answer= V=134.04

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3 years ago
if you horizontally strech the quadratic parent function, f(x)=x^2, by a factor of 4, what is the equation of the new function?
max2010maxim [7]

Answer:

     g(x) = x^2/16

Step-by-step explanation:

To stretch a function horizontally by a factor of k, replace x with x/k.

You want a stretch factor of 4, so your function is ...

  g(x) = f(x/4) = (x/4)^2

  g(x) = x^2/16

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The attached graph shows the horizontal stretch.

8 0
2 years ago
A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th
irga5000 [103]

Answer:

The rocket hits the ground at a time of 11.59 seconds.

Step-by-step explanation:

The height of the rocket, after x seconds, is given by the following equation:

y = -16x^2 + 177x + 98

It hits the ground when y = 0, so we have to find x for which y = 0, which is a quadratic equation.

Finding the roots of a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this question:

y = -16x^2 + 177x + 98

-16x^2 + 177x + 98 = 0

So

a = -16, b = 177, c = 98

\bigtriangleup = 177^{2} - 4(-16)(98) = 37601

x_{1} = \frac{-177 + \sqrt{37601}}{2*(-16)} = -0.53

x_{2} = \frac{-177 - \sqrt{37601}}{2*(-16)} = 11.59

Since time is a positive measure, the rocket hits the ground at a time of 11.59 seconds.

4 0
3 years ago
On the graph shown, what is f(-1)? (5 points) The first segment joints the point negative three comma five exclusively and negat
tatiyna
ANSWER

f( - 1) = 2

EXPLANATION

The given function is a piecewise defined function.

f( - 1)
is the y-value that corresponds to
x = - 1.

To determine that y-value, we need to trace from
x = - 1
to where it meets the graph.

We then trace to the y-axis to determine the corresponding y-value as shown in the diagram.

From the graph, we can see that this x-value corresponds to a y-value of
2

This implies that, when
x = - 1,y = 2

Therefore
f( - 1) = 2
See graph.

8 0
3 years ago
1. Which one of the following statements is true of perpendicular lines?
Dovator [93]
Only D is correct, it intersects at 90 degrees so it cant be obtuse or acute and never intersecting would be parallel lines <span />
7 0
3 years ago
Read 2 more answers
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