A local health clinic surveys its patients about their waterdrinking habits. It found the data is normally distributed,the mean
1 answer:
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data:
water drinking habits:
mean = 62 ounces
standard deviation = 5.2 ounces
Step 02:
normally distribution:
95% ===> 2 SD
(62 + 5.2 + 5.2) ounces = 72.4 ounces ==> + 2 SD
(62 - 5.2 - 5.2) ounces = 51.6 ounces ==> - 2 SD
The answer is:
51.6 ounces - 72.4 ounces
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Answer:
Gila Monster is 1.54 times that of Chuckwalla.
Step-by-step explanation:
Given:
Average Length of Gila Monster = 0.608 m
Average Length of Chuckwalla = 0.395 m
We need to find the number of times the Gila monster is as the Chuckwalla.
Solution:
Now we know that;
To find the number of times the Gila monster is as the Chuckwalla we will divide the Average Length of Gila Monster by Average Length of Chuckwalla.
framing in equation form we get;
number of times the Gila monster is as the Chuckwalla =
Rounding to nearest hundredth's we get;
number of times the Gila monster is as the Chuckwalla = 1.54
Hence Gila Monster is 1.54 times that of Chuckwalla.