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The equation of the line which has a gradient of 2 and passes through the point (1,4) is y = 2x + 2.
We have given that,
A line that has a gradient of 2 and passes through the line (1, 4).
We have to determine the equation of the line,
<h3>What is the gradient?</h3>
The gradient also known as the slope is the defined as
Gradient (m) = change in y coordinate / change in x coordinate
The equation of a line passing through a given point is given by the following equation
y – y₁ = m(x – x₁)
How to determine the equation of the line passing through point (1,4)
x coordinate (x₁) = 1
y coordinate (y₁) = 4
Gradient (m) = 2
Equation =
y – y₁ = m(x – x₁)
y – 4 = 2(x – 1)
Clear bracket
y – 4 = 2x – 2
Make y the subject by adding 4 to both sides
y – 4 + 4 = 2x – 2 + 4
y = 2x + 2
The equation of the line which has a gradient of 2 and passes through the point (1,4) is y = 2x + 2.
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Answer:
x = 80
Step-by-step explanation:
Combine − 3/5x and 7/20x to get -19/20x.
Then combine -19/20x and 1/4x and you get -7/10x.
Then you multiply both sides by -10/7 which is the reciprocal of -7/10.
Make -56(-10) one fraction.
Multiply -56 and -10 and you get 560.
Then divide 560 by 7 to get 80.
Answer:
3.6 since h = 3.6
Step-by-step explanation:
First you need to find the common denominator. Think of a number that both 2 and 5 can go in to evenly. 10 is the best number, so, make both denominators 10. What you do to the bottom, you must do to the top.
Now your equation is 5/10-2/10
Your answer is 3/10
