Question 1 of 29
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Given are three married couples.
So, let us assume there are 3 men and 3 women
They are sitting in a row of 6 empty seats
There is a definite order constraint that each woman will sit left to her husband. The first woman gets 3 options to choose from 3 available seats. The second woman has two options left as already one seat is filled by the first woman. The last woman has one option left. So, it is
So, number of ways is 3! = = 6 ways.
Answer:
i (or no solution if you haven't learned about imaginary numbers yet)
Step-by-step explanation:
The first thing you want to do is isolate x, or get x alone.
7x²+46=32
=> 7x²+46-46=32-46
=>7x²=-14
=>7x²÷7=-14÷7
=>x²=-2
If you have learned about imaginary numbers read on. If not, you have to realize that squaring any number can't result in a negative number. This means that there is no solution.
If you have learned about imaginary numbers, read on.
Now that you have x^2=-2, you can take the square root of both sides.
x=
Using a property about square roots (I don't know what it's called)
the equation becomes:
x=
And since =i, you can substitute in this value in to get x=i
.