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3 years ago

Answers for how to draw a model for 0.16

1 answer:

5 0

0.16 = 16/100

simplify 16/100 = 4/25

21/25, 4/25

as a percent
0.16 = 16%
84%, 16%

0.16 = 1/6

draw 100 squares (base ten blocks)., shade 16 of them

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Kristina lives 24.5 miles from the nearest mall Betn lives 2 1/2 times the distance from the mal then Kristina does. How mory mi

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Answer:

61.25

Step-by-step explanation:

2 1/2 is 2.5 in decimal.

24.5*2.5

Multiplying 24.5 by 2.5 gives 61.25

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3 years ago

60% of 75<br> find the percent.<br><br> please help! :o

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Answer:15

Step-by-step explanation:

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3 years ago

Which answers describe the shape below? Check all that apply.

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Answer:

Step-by-step explanation:

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Find the area of the parallelogram. Please this is due today. Thank you.

scZoUnD [109]

894 mi^2

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3 years ago

Area of a triangle with points at (-9,5), (6,10), and (2,-10)

Ann [662]

First we are going to draw the triangle using the given coordinates.
Next, we are going to use the distance formula to find the sides of our triangle.
Distance formula: $d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Distance from point A to point B:
$d_{AB}= \sqrt{[6-(-9)]^2+(10-5)^2}$
$d_{AB}= \sqrt{(6+9)^2+(10-5)^2}$
$d_{AB}= \sqrt{(15)^2+(5)^2}$
$d_{AB}= \sqrt{225+25}$
$d_{AB}= \sqrt{250}$
$d_{AB}=15.81$

Distance from point A to point C:
$d_{AC}= \sqrt{[2-(-9)]^2+(-10-5)^2}$
$d_{AC}= \sqrt{(2+9)^2+(-10-5)^2}$
$d_{AC}= \sqrt{11^2+(-15)^2}$
$d_{AC}= \sqrt{121+225}$
$d_{AC}= \sqrt{346}$
$d_{AC}= 18.60$

Distance from point B from point C
$d_{BC}= \sqrt{(2-6)^2+(-10-10)^2}$
$d_{BC}= \sqrt{(-4)^2+(-20)^2}$
$d_{BC}= \sqrt{16+400}$
$d_{BC}= \sqrt{416}$
$d_{BC}=20.40$

Now, we are going to find the semi-perimeter of our triangle using the semi-perimeter formula:
$s= \frac{AB+AC+BC}{2}$
$s= \frac{15.81+18.60+20.40}{2}$
$s= \frac{54.81}{2}$
$s=27.41$

Finally, to find the area of our triangle, we are going to use Heron's formula:
$A= \sqrt{s(s-AB)(s-AC)(s-BC)}$
$A=\sqrt{27.41(27.41-15.81)(27.41-18.60)(27.41-20.40)}$
$A= \sqrt{27.41(11.6)(8.81)(7.01)}$
$A=140.13$

We can conclude that the perimeter of our triangle is 140.13 square units.

3 0

3 years ago