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Serga [27]
3 years ago
13

Write the equation in slope intercept form and pls show your work.5x=2y-3​

Mathematics
1 answer:
jeka57 [31]3 years ago
5 0
Slope Intercept Form : y= mx + b
FIRST: move the -3 over to the 5x side.
5x+3=2y
SECOND: divide the two from both sides
5/2x + 3/2 = y or y = 5/2x + 3/2
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Someone help pls :,)
Semenov [28]

Answer:

W = 87 degrees

Step-by-step explanation:

First we can rearrange the question so that W is isolated on the left side, which we do by dividing both sides by tan:

tanW/tan = 19.0811/tan

W = 19.0811/tan

Now we can use the inverse tan function on the calculator (tan^{-1}) to calculate it:

W = 19.0811 x tan^{-1}

W = 87 degrees

Hope this helped!

8 0
3 years ago
4, 14, 6, 9, 21, 3, 7, 10
nekit [7.7K]
The correct answer is C.
5 0
4 years ago
Please help hard math
Korvikt [17]

The correct answer is a.

Inside the function it says x+2, and a +2 means it is to the left (direction is opposite of the sign)

The 3 on the outside of the function shows how the steepness, or slope will change. The first is correct because slope is rise over run, and if you go from one point to another, you'll see that it is up 3 and over 1, or 3/1, or 3.

6 0
3 years ago
I NEED HELP PLEASE HELP!!! IF YOU ANSWER THE FASTEST THEN I WILL AWARD BRAINLIEST ANSWER AND EXTRA!!!
horrorfan [7]
Yes it is a even number because the numbers that add up may equal the equal number if that answer is correct
4 0
4 years ago
What is the probability of obtaining 5 heads from 5 coin flips? Give your answer to 5 decimal places.
katovenus [111]

Answer:

0.03125 = 3.125% probability of obtaining 5 heads from 5 coin flips.

Step-by-step explanation:

For each coin flip, there are only two possible outcomes. Either it is heads, or it is tails. The probabilities for each flip are independent from each other. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

For each coin toss, heads and tails are equally as likely, so p = \frac{1}{2} = 0.5}

What is the probability of obtaining 5 heads from 5 coin flips?

This is P(X = 5) when n = 5.

So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{5,5}.(0.5)^{5}.(0.5)^{0} = 0.03125

0.03125 = 3.125% probability of obtaining 5 heads from 5 coin flips.

6 0
3 years ago
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