Solution:
4.2 x 10^6 bp/10^3 bp/seconds = 4.2 + 103 s which is 4200 seconds and equivalents to 70 minutes
In addition, assuming a pause of 2 seconds for re initiating after completing every okazaki fragment and assuming the okazaki fragments average 1000 nucleotide long.
4.2 x 10^6 bp/10^3 bp = 4200 okazaki fragments 4200 * 2 seconds = 8400 seconds which is 140 minutes or 2 hours 20 minutes of pauses alone.
Therefore, overall time would be pauses plus the 70 minutes so total time of 210 minutes. Assuming that the replisome completely disassociates from the DNA after every okazaki fragment and must spend one-minute rebinding.
4200 okazaki fragments. 60 seconds rebinding time per fragment: 4200 x 1 minute = 4200 minutes rebinding time plus 70 minutes for actual replication. 4200 minutes is 70 hours which is almost 3 days.
The answer is: D four haploid gametes
Answer:
Explanation:
Option D: <u><em>Increasing the mass by sitting people inside</em></u>
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Hope this helps, mark me brainiest
Answer:
Asexual and Sexual reproduction.
Explanation:
Reproduction can either have one or two parents. Based on this there is two types of reproduction:
Asexual: A type of reproduction where a single parent is divided by itself and reproduce its offspring.
Sexual: A process where two parents participate in producing their offspring.
Answer:
What do I do with this information? XD