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3 years ago

9

What is the value of the expression (25+25)×310?

1 answer:

MrRa [10]3 years ago

3 0

The anwser is 15,500

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if mike invests 2000 in the bank at a simple interest rate of 5.3% for 10 years how much interest will he make?

Tems11 [23]

Answer:

$1060

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 5.3%/100 = 0.053 per year,

then, solving our equation

I = 2000 × 0.053 × 10 = 1060

I = $ 1,060.00

The simple interest accumulated

on a principal of $ 2,000.00

at a rate of 5.3% per year

for 10 years is $ 1,060.00.

6 0

2 years ago

There were 800 farmers' markets initially in the USA in 2012. In 2013, the number of farmers' markets was 1.25 times the initial

zavuch27 [327]

For this case we have a function of the form:
$y = A * (b) ^ x
$
Where,
A: it is the initial amount
b: is the growth rate
x: is the number of years
Substituting values we have:
$y = 800 * (1.25) ^ x$
We have a growing exponential function because the value of b is greater than 1.
Answer:
See attached image.

8 0

3 years ago

Read 2 more answers

A ball is thrown and it follows a parabolic path. At each horizontal distance (x) the following equation models the ball’s heigh

Nataly_w [17]

Answer D). 9 ft is correct

Height of the ball at a horizontal distance of 10 feet is 9 ft

Step-by-step explanation:

A ball is thrown and it follows a parabolic path. At each horizontal distance (x) the following equation models the ball’s height (y).

Y(x) = $-0.02x^{2} +0.8x+3$

Question asked is " What will be height (Y) of the ball when X=10 ft "

Simply putting value of X in given equation

we get,

Y(x) = $-0.02x^{2} +0.8x+3$

Y(x) = $-0.02(10)^{2} +0.8(10)+3$

Y(x) = $-0.02(100)} +8+3$

Y(x) = $-2 +8+3$

Y(x) = $9$

<em>Therefore,</em> Height of the ball at a horizontal distance of 10 feet is 9 ft

Answer D. 9 ft is correct

6 0

3 years ago

What is the line of a slope that has an equation of y=x-3?

Dovator [93]

The slope is the number in front of the x. In this equation it is 1.

4 0

3 years ago

Read 2 more answers

Lesson: 1.08Given this function: f(x) = 4 cos(TTX) + 1Find the following and be sure to show work for period, maximum, and minim

Ber [7]

The given function is

$f(x)=4\cos \text{(}\pi x)+1$

The general form of the cosine function is

$y=a\cos (bx+c)+d$

a is the amplitude

2pi/b is the period

c is the phase shift

d is the vertical shift

By comparing the two functions

a = 4

b = pi

c = 0

d = 1

Then its period is

$\begin{gathered} \text{Period}=\frac{2\pi}{\pi} \\ \text{Period}=2 \end{gathered}$

The equation of the midline is

$y_{ml}=\frac{y_{\max }+y_{\min }}{2}$

Since the maximum is at the greatest value of cos, which is 1, then

$\begin{gathered} y_{\max }=4(1)+1 \\ y_{\max }=5 \end{gathered}$

Since the minimum is at the smallest value of cos, which is -1, then

$\begin{gathered} y_{\min }=4(-1)+1 \\ y_{\min }=-4+1 \\ y_{\min }=-3 \end{gathered}$

Then substitute them in the equation of the midline

$\begin{gathered} y_{ml}=\frac{5+(-3)}{2} \\ y_{ml}=\frac{2}{2} \\ y_{ml}=1 \end{gathered}$

The answers are:

Period = 2

Equation of the midline is y = 1

Maximum = 5

Minimum = -3

3 0

9 months ago