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PtichkaEL [24]
1 year ago
9

State the domain of 1b, then determine the equation of any vertical asymptotes and/or coordinates of any holes in the graph of t

he function.

Mathematics
1 answer:
Katena32 [7]1 year ago
6 0

We have

f(x)=\frac{2x^2+x}{x^2-5x+6}

First we will factorize the function

f(x)=\frac{x(2x+1)}{\mleft(x-2\mright)(x-3)}

The domain is

\: \mleft(-\infty\: ,\: 2\mright)\cup\mleft(2,\: 3\mright)\cup\mleft(3,\: \infty\: \mright)

In this case, we have two vertical asymptotes

x-2=0

x=2

x-3=0

x=3

ANSWER

The domain is

\: \mleft(-\infty\: ,\: 2\mright)\cup\mleft(2,\: 3\mright)\cup\mleft(3,\: \infty\: \mright)

The vertical asymtotes

x-2=0

x=2

x-3=0

x=3

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Nimfa-mama [501]

The question was incomplete. Below you will find the missing content.

In the figure below, BL, AM, and CK are medians of △ABC. If KC = 108 and OC = 2n + 10, then n=

The picture is attached below.

The value of n is 31.

The median is the line connecting the vertex and its midpoint on the opposite side of the triangle.

The intersection of all 3 medians of the triangle is called the centroid.

As we know centroid divides the median in the ratio of 2:1.

In the given picture,

Medians of triangle △ABC are AM, BL, and CK.

So the centroid of the triangle is O.

Given that KC= 108

As the centroid O divides the line KC in 2:1.

Let OC=2x

KO= X

As KC= KO+OC

⇒ 108= x+2x

⇒ 3x=108

⇒ x=108/3

⇒ x=36

Then OC= 2x= 2*36= 72

As given in the question OC= 2n+10

putting the value of OC in above equation

⇒ 72= 2n+10

⇒ 2n= 72-10

⇒ 2n=62

⇒ n=62/2

⇒n=31

Therefore the value of n is 31.

Learn more about the median of the triangle

here: brainly.com/question/2264495

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