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PtichkaEL [24]
1 year ago
9

State the domain of 1b, then determine the equation of any vertical asymptotes and/or coordinates of any holes in the graph of t

he function.

Mathematics
1 answer:
Katena32 [7]1 year ago
6 0

We have

f(x)=\frac{2x^2+x}{x^2-5x+6}

First we will factorize the function

f(x)=\frac{x(2x+1)}{\mleft(x-2\mright)(x-3)}

The domain is

\: \mleft(-\infty\: ,\: 2\mright)\cup\mleft(2,\: 3\mright)\cup\mleft(3,\: \infty\: \mright)

In this case, we have two vertical asymptotes

x-2=0

x=2

x-3=0

x=3

ANSWER

The domain is

\: \mleft(-\infty\: ,\: 2\mright)\cup\mleft(2,\: 3\mright)\cup\mleft(3,\: \infty\: \mright)

The vertical asymtotes

x-2=0

x=2

x-3=0

x=3

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2x-py=5 and 4x+5y+q=0.
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Answer:

q = 1 and p = 3

Step-by-step explanation:

Since we are already given the value of x and y, then it will be easy to get what p and q is. What is needed to be done is just to insert the values of x and y in both equations

For equation 1

2x -py = 5

insert x = q and y = -1

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for the second equation, we do same

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q = 5/5 = 1

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p = 5-2

p = 3

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