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Airida [17]
3 years ago
12

A sphere with a radius of 4mm how do i find the answer​

Mathematics
2 answers:
Yuri [45]3 years ago
8 0

Answer:

201.06

Step-by-step explanation:

lutik1710 [3]3 years ago
3 0

Answer:

a = 200.96 mm²

Step-by-step explanation:

a = 4 (3.14) (4²)

a = 200.96 mm²

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Else purchased a prepaid phone card for $15. Long distance calls cost 6 cents a minute using this card. Elsa used her card only
Ede4ka [16]

Answer:

25 minutes

Step-by-step explanation:

First you subtract the original amount on the card from the remaining amount left.

So you can get the amount of money spent on that call.

$15 - $13.50 = $1.50

Then you divide that number by how much it cost per minute.

$1.50 ÷ 6 = 0.25

Then you get your answer!

She was on the phone for 25 minutes

7 0
3 years ago
How can you tell when a pattern shows counting on by tens?
Anastaziya [24]
You can tell by using the time tables
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Janna is measuring the dimensions of her bedroom to determine how much paint she should buy for the walls. If her measuring tape
Otrada [13]

3.8907. y0.01 length wanna

7 0
3 years ago
You play two games against the same opponent. The probability you win the first game is 0.4. If you win the first game, the prob
Ilia_Sergeevich [38]

Answer:

a) No

b) 42%

c) 8%

d) X               0                 1                2

   P(X)           42%            50%         8%

e) 0.62

Step-by-step explanation:

a) No, the two games are not independent because the the probability you win the second game is dependent on the probability that you win or lose the second game.

b) P(lose first game) = 1 - P(win first game) = 1 - 0.4 = 0.6

P(lose second game) = 1 - P(win second game) = 1 - 0.3 = 0.7

P(lose both games) = P(lose first game)  × P(lose second game) = 0.6 × 0.7 = 0.42 = 42%

c)   P(win first game)  = 0.4

P(win second game) = 0.2

P(win both games) = P(win first game)  × P(win second game) = 0.4 × 0.2 = 0.08 = 8%

d) X               0                 1                2

   P(X)           42%            50%         8%

P(X = 0)  =  P(lose both games) = P(lose first game)  × P(lose second game) = 0.6 × 0.7 = 0.42 = 42%

P(X = 1) = [ P(lose first game)  × P(win second game)] + [ P(win first game)  × P(lose second game)] = ( 0.6 × 0.3) + (0.4 × 0.8) = 0.18 + 0.32 = 0.5 = 50%

e) The expected value  \mu=\Sigma}xP(x)= (0*0.42)+(1*0.5)+(2*0.08)=0.66

f) Variance \sigma^2=\Sigma(x-\mu^2)p(x)= (0-0.66)^2*0.42+ (1-0.66)^2*0.5+ (2-0.66)^2*0.08=0.3844

Standard deviation \sigma=\sqrt{variance} = \sqrt{0.3844}=0.62

8 0
3 years ago
What is 50 times 50 times 50 times 20
Ronch [10]
*You could use a calculator
50 times 50 times 50 times 20 equals <span>2500000</span>
Your answer is <em>2500000</em>
6 0
3 years ago
Read 2 more answers
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