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Airida [17]
3 years ago
12

A sphere with a radius of 4mm how do i find the answer​

Mathematics
2 answers:
Yuri [45]3 years ago
8 0

Answer:

201.06

Step-by-step explanation:

lutik1710 [3]3 years ago
3 0

Answer:

a = 200.96 mm²

Step-by-step explanation:

a = 4 (3.14) (4²)

a = 200.96 mm²

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a cafe offers senior citizens a 15% discount off its regular rice of 8.95 for the dinner buffet. what percent of the regular pri
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Answer: 85%

Step-by-step explanation:

The regular price is 8.95, with a 15% discount for Seniors. So the senior price would be 100%-15%=85% of the regular price.

4 0
3 years ago
Simplify the expression<br> (1 + 1/x)(1 - 2/x+1)(1 + 2/x-1)
valentinak56 [21]

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Step-by-step explanation:

3 0
2 years ago
(28 and 29) I really need help
scoundrel [369]

Answer:

28 is 11/60

29 is 7/30

Step-by-step explanation:

5 0
3 years ago
For problems 29 - 31 the graph of a quadratic function y=ax^2 + bx + c is shown. Tell whether the discriminant of ax^2 + bx + c
Elan Coil [88]

Answer:

29) discriminant  is positive

30) discriminant  is 0

31) discriminant  is negative

Step-by-step explanation:

the graph of a quadratic function y=ax^2 + bx + c is shown. Tell whether the discriminant of ax^2 + bx + c = 0 is positive, negative, or zero.

In the graph of question number 29 we can see that the graph intersects the x axis at two points

so the equation has 2 solutions.

When the equation has two solution then the discriminant is positive

In the graph of question number 30 we can see that the graph intersects the x axis at only one point

so the equation has only  1 solution.

When the equation has only one solution then the discriminant is equal to 0

In the graph of question number 30 we can see that the graph does not intersects the x axis  

so the equation has 2 imaginary solutions.

When the equation has two imaginary solutions then the discriminant is negative

3 0
3 years ago
A triangle with a base of 16 cm and a height of 9 cm.
bagirrra123 [75]

Answer: 288

Step-by-step explanation:

(16x9)x2

3 0
2 years ago
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