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saul85 [17]
11 months ago
15

Using the rotation R, can you create a function R(ABCD) that is equivalent to the reflection of ABCD across both the x-axis and

y-axis?
Mathematics
1 answer:
galben [10]11 months ago
6 0

The reflection over the x-axis is given by:

R(x,y)\to(-x,y)

And the reflection over the y-axis is given by:

R(x,y)\to(x,-y)

Thus, a function that is equivalent to the reflection of ABCD across both axis would be:

R(x,y)\to(-x,-y)

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By definition, the determinant equals ad - bc. What is the value of when x = -2 and y = 3? I NEED HELP PLEASE
sergiy2304 [10]

Answer:

<h3>B. -84</h3>

Step-by-step explanation:

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= 20xy - 6xy

= 14xy

Given x = -2 and y = 3

Determinant = 14(-2)(3)

Determinant = -28*3

Determinant = -84

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6 0
3 years ago
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Andre45 [30]
X = 3 and x = 4 will make the polynomial = 0

answer
C. 3 and 4
4 0
3 years ago
Read 2 more answers
Use the exterior angle theorem to find the value of x in the triangle below.
Arisa [49]

Answer:

Option A

Step-by-step explanation:

By using the definition of an exterior angle of a triangle,

"Measure of the exterior angle of a triangle is equal to the sum of measures of the opposite interior angles"

m∠STP = m∠SWT + m∠STW

Substitute the measures of the angles from the picture attached,

15x = (7x + 1) + (7x + 6)

15x = (7x + 7x) + (1 + 6)

15x = 14x + 7

15x - 14x = 7

x = 7

Therefore, Option A will be the correct option.

7 0
3 years ago
Rewrite x2 − 6x + 7 = 0 in the form (x − a)2 = b, where a and b are integers, to determine the a and b values.
Setler79 [48]

Answer:

Therefore values of a and b are

a=3\ and\ b = 2

Step-by-step explanation:

Rewrite x^{2}-6x+7=0 in the form

(x-a)^{2}=b

where a and b are integers,

To Find:

a = ?

b = ?

Solution:

x^{2}-6x+7=0 ..............Given

Which can be written as

x^{2}-6x=-7

(\frac{1}{2} coefficient\ of\ x)^{2}=(\frac{1}{2}\times -6)^{2}=9

Adding half coefficient of X square on both the side we get

x^{2}-6x+9=-7+9=2 ...................( 1 )

By identity we have (A - B)² =A² - 2AB + B²

Therefore,

x^{2}-6x+9=x^{2}-2\times 3\times x+3^{2}=(x-3)^{2}

Substituting in equation 1 we get

(x-3)^{2}=2

Which is in the form of

(x-a)^{2}=b

On comparing we get

a = 3 and b = 2

Therefore values of a and b are

a=3\ and\ b = 2

4 0
3 years ago
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