O EXPONENTIAL AND LOGARITHMIC FUNCTIONSExpanding a logarithmic expression: Problem type 1

Mathematics

1 answer:

Ira Lisetskai [31]1 year ago

8 0

Given:

a logarithm is given as

$log(z^5x)$

Find:

we have to expand the given logarithm expressionusing properties of logarithm.

Explanation:

we know from the properties of logarithm that

$\begin{gathered} log(m^n)=nlog(m) \\ and \\ log(mn)=log(m)+log(n) \end{gathered}$

we will use above properties to expand the given logarithm expression as follows

$log(z^5x)=logz^5+logx=5logz+logx$

Therefore, the expansion of the given logarithm is 5 log(z)+ log(x)

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What percent of the June budget was for babysitting and movies (to the nearest tenth)?

Aleonysh [2.5K]

The monthly expenses are found below:

Mortgage - $752 Tim's Chevron - $23Johnny's Allowance - $8Electric - $176Jenny-babysitting - $12Movie - $14Dry Cleaning - $41Tithe - $85,Credit Card - $150Food - $101Phone - $45Water - $16 Car - $272

Adding all the expenses, will give us a total of $1695.

To get the percent which is allocated for movie and the baby sitting:

Add the amount for the two then divide that to the total then multiply it by 100%
= 12 + 14 / 1695 x 100%
= 26 / 1695 x 100%
= 0.015339233 x 100%

=1.5%
The answer is 1.5%

3 0

3 years ago

Working alone Ryan can dig a 10ft by 10ft hole in five hours castel can dig the same same hole in six how long would it take the

Sergeeva-Olga [200]

Answer:

The time taken by both when they work together is 2 hours 42 minutes .

Step-by-step explanation:

Given as :

The time taken by Ryan to dig 10 ft by 10 ft hole = x = 5 hours

The time taken bu Castel to dig 10 ft by 10 ft hole = y = 6 hours

Let The time taken by both when they work together = z hours

<u>According to question</u>