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dybincka [34]
3 years ago
14

Can someone help me to solve this question sec(x)sin(x)-2sin(x)=0 [0,2pi) ? ASAP!!!!!

Mathematics
1 answer:
BigorU [14]3 years ago
3 0

Answer:

x = 0, π/3, π, 5π/3

Step-by-step explanation:

sec(x)sin(x) - 2sin(x) = 0

factor out sin(x)

sin(x)[sec(x) - 2] = 0

then solve by splitting into two parts:

sin(x) = 0 and sec(x) - 2 = 0

x = 0, π    and x = π/3, 5π/3 then plug in to original equation to check

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