All categories

4 years ago

Can someone help me to solve this question sec(x)sin(x)-2sin(x)=0 [0,2pi) ? ASAP!!!!!

Mathematics

1 answer:

BigorU [14]4 years ago

3 0

Answer:

x = 0, π/3, π, 5π/3

Step-by-step explanation:

sec(x)sin(x) - 2sin(x) = 0

factor out sin(x)

sin(x)[sec(x) - 2] = 0

then solve by splitting into two parts:

sin(x) = 0 and sec(x) - 2 = 0

x = 0, π and x = π/3, 5π/3 then plug in to original equation to check

You might be interested in

Find the largest possible revenue from the demand equation "Q= -2p + 1000

Mariana [72]

Revenue=quantity x price= (-2p+1000) (p)= -2p^2+1000p
The maximum revenue will occur when the first derivative is zero so when 2(-2p)+1000=0;p=250
Which generates 125,000 in revenue
Try prices of 245 and 255 and you will see they both are less than 250 thereby proving the max revenue is 250

3 0

3 years ago

You need to put your reindeer, Ezekiel, Lancer, Rudy, and Jebediah, in a single-file line to pull your sleigh. However, Jebediah

Korvikt [17]

Answer:

Well to start out you have 5 reindeer. If you glue Lancer and Ezekiel together you only have 4 units to arrange in different orders. That number is 24. But for each of those, Lancer and Ezekiel can be arranged in two ways... with Lancer in front of the pair or in the back of the pair. So altogether there are 48 ways to arrange the five reindeer with Lancer and Ezekiel always being together.

5 0

3 years ago

Read 2 more answers

Solve for x.<br> 9x = 27<br> I need help for this problem.

AlekseyPX

X=3 !!!! Have a good day

8 0

3 years ago

Read 2 more answers

Hasil darab umur

Alex787 [66]

Answer:

nojkl.kj

Step-by-step explanation:

lklkjl,kjkl

3 0

3 years ago

A jet skier departs from Pier 1, travels 796 meters directly to a buoy, makes a turn, and travels 1054 meters directly to Pier 2

Anastasy [175]

9514 1404 393

Answer:

160°

Step-by-step explanation:

The path is a triangle with side lengths 796, 1054, and 411 meters. The turn is opposite the short side. The interior angle of the triangle at that point can be computed using the law of cosines. If we label the sides a, b, c, respectively, then ...

c² = a² + b² - 2ab·cos(C)

C = arccos((a² +b² -c²)/(2ab)) = arccos(1575611/1677968) ≈ 20.116°

The external angle at the buoy is 180° -20° = 160°.

The jet skier's turn was about 160°.

3 0

3 years ago