When Factor what is the least common factor of 4 and 5

4. If DF = 9x - 39, find EF. Help I’m so confused!!!!

topjm [15]

Answer:

EF =58

Step-by-step explanation:

from the illustration,

EF =DF - DE

given that DF =9x-39 , DE =47 EF=3x +10

substitute them into the formula,

3x +10=9x-39 - 47

solving for x

3x +10 =9x -86

grouping like terms

3x - 9x =-86 -10

-6x=-96

dividing through by -6

 $\frac{ - 6x}{ - 6} = \frac{ - 96}{ - 6}$ 

 $x = \frac{96}{6}$ 

 $x = 16$ 

but EF=3x+10

substitute x=16 into it to get the EF

EF= 3(16)+10

EF=48+10

EF=58

6 0

3 years ago

Read 2 more answers

Aiden wrote a riddle: Five less than 1/5 times a number is the same as the sume of the number and 1/3. Find the number.

Brrunno [24]

The number is -6.67

Solution:

Let "n" be the number

From given,

$\text{ Five less than 1/5 times a number } = \frac{1}{5}n - 5 = \frac{5}{n} - 5$

$\text{Sum of number and 1/3 } = n + \frac{1}{3} =\frac{3n+1}{3}$

Given that,

Five less than 1/5 times a number is the same as the sum of the number and 1/3

Therefore, we get,

$\frac{n}{5} - 5 = n + \frac{1}{3}\\\\Simplify\ the\ expression\\\\n - 25 = 5(n + \frac{1}{3})\\\\n - 25 = 5n + \frac{5}{3}\\\\n - 25 = \frac{15n + 5}{3}\\\\3n - 75 = 15n + 5\\\\12n = -80\\\\n = -6.67$

Thus the number is -6.67

7 0

3 years ago

The first term of an arithmetic sequence is -5, and the tenth term is 13. Find the common difference.

dlinn [17]

$\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference}\\[-0.5em] \hrulefill\\ a_1=-5\\ n=10\\ a_{10}=13 \end{cases} \\\\\\ a_{10}=a_1+(10-1)d\implies 13=-5+(10-1)d \\\\\\ 13=-5+9d\implies 18=9d\implies \cfrac{18}{9}=d\implies \boxed{2=d}$