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Alecsey [184]
1 year ago
14

PLS HELP!!! I attached the question in the picture below

Mathematics
1 answer:
Iteru [2.4K]1 year ago
8 0
Take a square root if both sides and you will get
a+6=7 and a+6=-7

For a+6=7
Subtract 6 from both sides
a=1

For a+6=-7
Again subtract 6 from both sides
a=-13

Therefore, the last answer is correct
You might be interested in
A rectangle has vertices at these coordinates.(3,6), (3,4), (6,4)What are the coordinates of the fourth vertex of the rectangle?
omeli [17]
Hi, i hope this helps! The coordinates are (6,6). I figured this out by plotting the given points and remembering that a rectangle has parallel sides and right angles :))

5 0
3 years ago
Solve the following system of equations graphically on the set of axes below. y=3x−3 , x+y=5
topjm [15]

Answer:

x=2, y=3

Step-by-step explanation:

First, graph both equations on a rectangular coordinate system (see attached screenshot). Then, simply figure out where these two lines intersect. Since they intersect at (2,3), x=2 and y=3.

Plugging these values in the equations for x and y, you can see if these are the correct answers:

(3)=3(2)-3, (2)+(3)=5

Since both of these are true, you have the right answer.

Hope this helps!

6 0
3 years ago
What is |-6,035| ?<br> Plz help
cluponka [151]
The absolute value is the distance between a number and zero. The distance between
-6035 and 0 is 6035
8 0
3 years ago
Read 2 more answers
What is the answer for 35 3/4 - 1/8
BabaBlast [244]

Steps:

1. since the least common multiple of 8 and 4 is 8, you would have to make both of the denominators 8.

2. 2 times 4 equals 8, 2 times 3 equals 6

3. 35 3/4 now becomes 35 6/8

4. your new problem is 35 6/8 - 1/8

5. 6 -1= 5

6. your answer is 35 5/8

4 0
3 years ago
What is the equation of the quadratic graph with a focus of (3, 1) and a directrix of y = 5?
lbvjy [14]

Answer:

The equation of the quadratic graph is f(x)= - (1/8) (x-3)^2 + 3 (second option)

Step-by-step explanation:

Focus: F=(3,1)=(xf, yf)→xf=3, yf=1

Directrix: y=5 (horizontal line), then the axis of the parabola is vertical, and the equation has the form:

f(x)=[1 / (4p)] (x-h)^2+k

where Vertex: V=(h,k)

The directix y=5 must intercept the axis of the parabola at the point (3,5), and the vertex is the midpoint between this point and the focus:

Vertex is the midpoint between (3,5) and (3,1):

h=(3+3)/2→h=6/2→h=3

k=(5+1)/2→k=6/2→k=3

Vertex: V=(h,k)→V=(3,3)

p=yf-k→p=1-3→p=-2

Replacing the values in the equation:

f(x)= [ 1 / (4(-2)) ] (x-3)^2 + 3

f(x)=[ 1 / (-8) ] (x-3)^2 + 3

f(x)= - (1/8) (x-3)^2 + 3

4 0
3 years ago
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