Answer:
An equation of the circle with centre (-2,1) and radius 3 is 
Option D is correct.
Step-by-step explanation:
Looking at the figure we get centre of circle C (-2,1) and radius of circle r = 3
The equation of circle is of form:
where (h,k) is centre and r is radius.
We have centre C (-2,1) so, we have h = -2 and k = 1
We have radius = 3 so, r = 3
Putting values in the equation and finding the required equation:

So, an equation of the circle with centre (-2,1) and radius 3 is 
Option D is correct.