F(x)=x^3-9x
and
g(x)=x^2-2x-3
so you just need to divide f(x) by g(x)
Therefore:
f(x)/g(x) = (x^3-9x) / (x^2-2x-3)
and of course you need to factor these two function to see if some factor would cancel another
x^3-9x = x(x^2-9)=x(x-3)(x+3)
and
x^2-2x-3 = (x-3)(x+1)
Answer:
811/16 i think
Step-by-step explanation:
Answer:
x=1/3 or 0.3
Step-by-step explanation:
Multiply to remove the fraction, then set equal to 0 and solve.
Answer:
7 adults, 12 students
Step-by-step explanation:
10 20 30 40 50
60 70
74 78 82 86 90
94 98 102 106 110 114 118
8*3+6-2
8*3=24
24+6=30
30-2=28
8*3+6-2=28
